All categories

3 years ago

Which equation shows a conservation of mass?

Physics

1 answer:

irina1246 [14]3 years ago

8 0

C. Nothing is lost or gained. It is equivalent.

You might be interested in

Question 1 2.5 cm= mm

Nookie1986 [14]

There’s 10mm in a cm: 22mm

8 0

3 years ago

Read 2 more answers

In an experiment to determine the s.h.c. of lead, a 0.80 kg block of lead is heated using a

gladu [14]

Answer:2.47

Explanation: did the math

8 0

2 years ago

An electron moving parallel to a uniform electric field increases its speed from 2.0 × 107 m/s to 4.0 × 107 m/s over a distance

jeka94

Answer:

$1.8\times 105 N/C$

Explanation:

We are given that

$u=2\times 10^7 m/s$

$v=4\times 10^7 m/s$

d=1.9 cm= $\frac{1.9}{100}=0.019 m$

Using 1m=100 cm

We have to find the electric field strength.

$v^2-u^2=2as$

Using the formula

$(4\times 10^7)^2-(2\times 10^7)^2=2a(0.019)$

$16\times 10^{14}-4\times 10^{14}=0.038a$

$0.038a=12\times 10^{14}$

$a=\frac{12}{0.038}\times 10^{14}=3.16\times 10^{16}m/s^2$

$q=1.6\times 10^{-19} C$

Mass of electron,m $=9.1\times 10^{-31} kg$

$E=\frac{ma}{q}$

Substitute the values

$E=\frac{9.1\times 10^{-31}\times 3.16\times 10^{16}}{1.6\times 10^{-19}}$

$E=1.8\times 105 N/C$

7 0

3 years ago

Coiling wire around an iron core and applying an electric current through the wire creates a temporary magnet called an electrom

Serggg [28]

Answer:

C) Use a battery with more voltage.

Explanation:

The equation for the magnetic field around a coil is given by,

B = μ₀NI

where,

B = Magnetic flux density

μ₀ = permeability

N = number of turns per meter

I = Current in the wire

So when using a higher voltage battery, more current passes through the battery as resistance of the wire remains the same.

5 0

2 years ago

Read 2 more answers

A 72 kg skydiver can be modeled as a rectangular "box" with dimensions 21 cm × 41 cm × 170 cm . if he falls feet first, his drag

LuckyWell [14K]

Formula for terminal velocity is:

Vt = √(2mg/ρACd)
Vt = terminal velocity = ?
m = mass of the falling object = 72 kg
g = gravitational acceleration = 9.81 m/s^2
Cd = drag coefficient = 0.80
ρ = density of the fluid/gas = 1.2 kg/m^3
A = projected area of the object (feet first) = 0.21 m * 0.41 m = 0.0861 m^2

Therefore:

Vt = √(2 * 72 * 9.81 / 1.2 * 0.0861 * 0.80)

Vt = 130.73 m/s

4 0

3 years ago