2.2 x 10^-5 um = _______ km

Physics

1 answer:

drek231 [11]4 years ago

3 0

The answer is 2.2 × 10^-14<span> kilometers

hope this helps</span>

You might be interested in

The acceleration of The Munster’s car is 9.71 m/s2 when he applies 5050 N of net force (by way of the engine). What is the mass

Ainat [17]

Given that,

Acceleration, a = 9.71 m/s²

Force, F = 5050 N

mass, m = ?

Since, we know that

F=ma

m= F/a

m= 5050/9.71

m= 520.08 kg

The mass of hi car is 520.08 kilograms.

4 0

3 years ago

A cable weighing 0.6 pounds per foot is attached to a small 70-pound robot, and then the robot is lowered into a 50-foot deep we

Sav [38]

Answer:

4600 ft.Ibs

Explanation:

Work done by the robot in climbing to the top of the well = work done in carrying the cable and itself + work done in carrying about average half the mass of the cable attached to the robot

Now work done = Force × distance = (( 70 +7 ) × 50 ft) + (( 0.6 × 50 ft) × 25 ) = 3850 + 750 = 4600 ft.Ibs

8 0

4 years ago

Which of the following types of energy is potential energy A. gravitational energy

katovenus [111]

There are many forms of energy, but they can all be put into two categories: kinetic and potential. Kinetic energy is motion––of waves, electrons, atoms, molecules, substances, and objects. Potential energy is stored energy and the energy of position––gravitational energy

4 0

3 years ago

A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o

Andrej [43]

Answer:

Recoil speed, $1.17\times 10^{-5}\ m/s$

Explanation:

Given that,

Mass of the comet fragment, $m_1=1.96\times 10^{13}\ kg$

Speed of the comet fragment, $v_1=6.5\times 10^4\ m/s$

Mass of Callisto, $m_2=1.08\times 10^{23}\ kg$

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

$m_1v_1=(m_2+m_2)V$

V is recoil speed of Callisto immediately after the collision.

$V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s$