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tino4ka555 [31]
3 years ago
12

A car has a momentum of 20,000 kg • m/s. what would the car’s momentum be if its velocity doubles? 10,000 kg • m/s 20,000 kg • m

/s 40,000 kg • m/s 80,000 kg • m/s
Physics
2 answers:
babunello [35]3 years ago
8 0
It would definitely be 40,000 <span>kg • m/s because if you double either the mass or velocity and the other stays the same, the momentum will double no matter what.</span>
Jet001 [13]3 years ago
7 0

Answer: 40,000 kg • m/s

Explanation:

the momentum of an object is defined as the product between its mass (m) and its velocity (v):

p=mv

From the formula, we see that there is a direct proportionality between the momentum, p, and the velocity, v. Therefore, if the velocity is doubled, then the momentum doubles as well.

In this problem, the initial momentum of the car is 20,000 kg • m/s. Therefore, if the velocity of the car is doubled, the momentum of the car will double as well, and it will becomes

2\cdot 20,000 kg \cdot m/s=40,000 kg m/s


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Answer:

The correct answers are the proportionality of the fields concerning distance, vector fields, and forces at a distance.

Explanation:

The similarities between magnetic fields and electric fields are that electric fields are produced by two charges that can be positive and negative. Magnetic fields are associated with two magnetic poles, although they are also produced by moving charges. Both fields are inversely proportional to the square of the distance between the sources, both fields are vectorial and both act by distant forces.

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Astronaut A can cover 10 meters per minute walking with the heavy shovel. What does
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Answer:

d) The speed of the astronaut

Explanation:

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Now let us understand why;

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A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular
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A swimmer bounces almost straight up from a diving board and falls vertically feet first into a pool.she starts with a speed of
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Answer:

a) 1.20227 seconds

b) 0.98674 m

c) 7.3942875 m/s

Explanation:

t = Time taken

u = Initial velocity = 4.4 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=4.4-9.81\times t\\\Rightarrow \frac{-4.4}{-9.81}=t\\\Rightarrow t=0.44852\ s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.4\times 0.44852+\frac{1}{2}\times -9.81\times 0.44852^2\\\Rightarrow s=0.98674\ m

b) Her highest height above the board is 0.98674 m

Total height she would fall is 0.98674+1.8 = 2.78674 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.78674=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.78674\times 2}{9.81}}\\\Rightarrow t=0.75375\ s

a) Her feet are in the air for 0.75375+0.44852 = 1.20227 seconds

v=u+at\\\Rightarrow v=0+9.81\times 0.75375\\\Rightarrow v=7.3942875\ m/s

c) Her velocity when her feet hit the water is 7.3942875 m/s

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