1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tino4ka555 [31]
3 years ago
12

A car has a momentum of 20,000 kg • m/s. what would the car’s momentum be if its velocity doubles? 10,000 kg • m/s 20,000 kg • m

/s 40,000 kg • m/s 80,000 kg • m/s
Physics
2 answers:
babunello [35]3 years ago
8 0
It would definitely be 40,000 <span>kg • m/s because if you double either the mass or velocity and the other stays the same, the momentum will double no matter what.</span>
Jet001 [13]3 years ago
7 0

Answer: 40,000 kg • m/s

Explanation:

the momentum of an object is defined as the product between its mass (m) and its velocity (v):

p=mv

From the formula, we see that there is a direct proportionality between the momentum, p, and the velocity, v. Therefore, if the velocity is doubled, then the momentum doubles as well.

In this problem, the initial momentum of the car is 20,000 kg • m/s. Therefore, if the velocity of the car is doubled, the momentum of the car will double as well, and it will becomes

2\cdot 20,000 kg \cdot m/s=40,000 kg m/s


You might be interested in
An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1
Ksivusya [100]
<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

                 F=\frac{GMm}{r^2}

           Where G =  6.67 x 10⁻¹¹ N m²/kg²

                       M = Mass of body 1

                       M = Mass of body 2

                       r = Distance between them

Here we have

                 M = Mass of Sun = 1.99×10³⁰ kg

                 m = Mass of asteroid = 4.00×10¹⁶ kg

                 F = 3.14×10¹³ N

Substituting

                   F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m

The asteroid is 4.11 x 10¹¹ m far from Sun

3 0
3 years ago
En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8
Ivanshal [37]

Answer:

v1=18.46m/s

v2=29.8cm/s

Explanation:

We know that

A=10cm\\T=2s

the equation of the motion is

x=Acos(\omega t)\\

we can calculate w by using

\omega=\frac{2\pi}{T}=\frac{2\pi}{2}=\pi

Hence, we have that

x=10cm*cos(\pi t)\\

the speed will be

v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46\frac{cm}{s}\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8\frac{cm}{s}

hope this helps!

6 0
3 years ago
A machine part has the shape of a solid uniform sphere of mass 205 g and diameter 4.10 cm. It is spinning about a frictionless a
kondor19780726 [428]

Answer:

Answer is in the following attachment.

                                                                                                                                                                                                 

Explanation:

3 0
3 years ago
A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 11.8 m/s directly upward.
Fantom [35]

Answer:

7.09683 m

1.20285 s

2.4057 s

11.8 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² (negative up, positive down)

From equation of motion we have

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11.8^2}{2\times -9.81}\\\Rightarrow s=7.09683\ m

The maximum height above the ground that the ball reaches is 7.09683 m

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-11.8}{-9.81}\\\Rightarrow t=1.20285\ s

Time taken to go up is 1.20285 s it will take the same time to come down so total time taken to reach the ground after it is shot is 1.20285+1.20285 = 2.4057 s

v=u+at\\\Rightarrow v=0+9.81\times 1.20285\\\Rightarrow v=11.8\ m/s

The velocity just before it hits the ground is 11.8 m/s

6 0
2 years ago
Two persons manage to push a motorcar of mass 1200 kg at uniform velocity along a level road, The same motorcar can be pushed by
densk [106]

Answer:

40N by each person.

Explanation:

8 0
3 years ago
Other questions:
  • Question 4. A tuning fork ‘A’ produces 6 beats/sec with another fork ‘B’ of un-known frequency. On
    14·1 answer
  • A thin coil has 17 rectangular turns of wire. When a current of 4 A runs through the coil, there is a total flux of 5 ✕ 10−3 T ·
    13·1 answer
  • . Egbert is in a rowboat four miles from the nearest point on Egbert a straight shoreline. He wishes to reach a house 12 miles f
    12·1 answer
  • A car accelerates uniformly in a straight line
    10·1 answer
  • PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!! 80 POINTS!!!!!!!!!!!!
    6·2 answers
  • A ball is thrown upward from an initial height of 1.5m the ball reaches a height of 5m then falls to the ground . What Is the di
    9·1 answer
  • To pop a balloon you stab it with a pencil. If the area of the pencil tip is .01 cm² and the pressure applied by the pencil to t
    11·1 answer
  • A rather devious student has built himself a slingshot, with the idea of firing
    5·1 answer
  • Select the correct answer.
    13·1 answer
  • Given the velocity v= ds dt and the initial position of a body moving along a coordinate line, find the body's position at time
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!