Answer:
Magnetic field, B = 0.199 T
Explanation:
It is given that,
Radius of circular loop, r = 11.7 cm = 0.117 m
Magnetic flux through the loop, 
The magnetic flux linked through the loop is :
Here, 
or
B = 0.199 T
So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.
(C). Remember gravity provides an acceleration of 9.81m/s^2, so the y component of velocity initial is zero because it isn’t already falling, and we have the height, so basically we use the kinematic equation vf^2=vi^2+2ad, substitute given values and you get vf^2=2(9.81)(65) which is 1275, when you take the square root you get 35.7m/s for final velocity
(B). Then you use vf=vi+at to get the equation 35.7=(9.81)t, when you divide out you get 3.64s for time t
(A). Finally, since we assume that there is no acceleration or deceleration horizonatally, we just multiply the time taken for it to hit the ground and the initial speed ((3.64)(35.7)) to get 129.96, with significant figures I would round that to 130 metres.
**this is in the order that I felt was easiest to answer**
<span>a cell producing an electric current directly from a chemical reaction
</span>
But I can help you if you need to answer this question
Dony
Answer:
0.915 Nm
Explanation:
1 revolution = 2π rad
We can use the following equation of motion to find out the acceleration acting on the disk
where ![\omega v = 2.5 rad/s is the final angular velocity of the disk, [tex]\omega_0](https://tex.z-dn.net/?f=%5Comega%20v%20%3D%202.5%20rad%2Fs%20is%20the%20final%20angular%20velocity%20of%20the%20disk%2C%20%5Btex%5D%5Comega_0)
= 0 rad/s is the initial velocity of the can when it starts from rest, 
is the angular distance traveled, 
is the angular acceleration of the disk, which we care looking for:
The moment of inertia of the solid disk is:
where m is the mass and R is the radius of the disk
The net torque applied is
