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nika2105 [10]
3 years ago
14

Who is responsible of refraction light 1/3 in eye

Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

The cornea is  responsible of refraction light 1/3 in eye.

<h3>What is the function of the cornea?</h3>

In addition to the protective function, it plays a fundamental role in the formation of vision. Transparent, it works like a lens over the iris, focusing light from the pupil towards the retina.

Normally, the cornea and lens deflect (refract) incoming light rays, focusing them on the retina. The shape of the cornea is fixed, but the lens changes shape to focus on objects at different distances from the eye.

See more about cornea at brainly.com/question/2297282

#SPJ12

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A crane lifts a 6.500 N weight 10 m in 180 seconds. What power is used?
Nostrana [21]
Power is work over time.

P= \frac{W}{t}

We can solve for work by using F*d

W=F*d = (6.500N)(10m) = 65 J

Now solve for power:

P= \frac{(65J)}{180s} = 0.361W&#10;&#10;P=0.361W
8 0
3 years ago
60 POINTS SO PLEASE HELP ME To add vectors in a straight line ______________ and ______________ are considered positive directio
tankabanditka [31]

Answer:

The answer to your question is

Explanation:

To add vectors in a straight line _<u>right</u>_________ and ___<u>upwards</u>_______ are considered positive directions. __<u>left</u>________ and __<u>downwards</u>____________ are considered negative directions.

I hope it helps you

7 0
3 years ago
If a box is pulled with a force of 100 N at an angle of 25
love history [14]

The X and Y components of the force are 90.63 Newton and 42.26 Newton respectively.

<u>Given the following data:</u>

  • Force = 100 Newton.
  • Angle of inclination = 25°

To determine the X and Y components of the force:

<h3>The horizontal component (X) of a force:</h3>

Mathematically, the horizontal component of a force is given by this formula:

F_x = Fcos \theta\\\\F_x =100 \times cos25\\\\F_x =100 \times 0.9063

Fx = 90.63 Newton.

<h3>The vertical component (Y) of tensional force:</h3>

Mathematically, the vertical component of a force is given by this formula:

F_y = Fsin \theta\\\\F_y =100 \times sin25\\\\F_y =100 \times 0.4226

Fy = 42.26 Newton.

Read more on horizontal component here: brainly.com/question/4080400

6 0
2 years ago
A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to
ryzh [129]

Answer:

a. The horizontal component of acceleration a₁ = 0.68 m/s²

The vertical component of acceleration a₂ = -0.11 m/s²

b. -9.19° = 350.81° from the the positive x-axis

Explanation:

The initial velocity v₁ of the fish is v₁ = 4.00i + 1.00j m/s. Its final velocity after accelerating for t = 19.0 s is v₂ =  17.0i - 1.00j m/s

a. The acceleration a = (v₂ - v₁)/t = [17.0i - 1.00j - (4.00i + 1.00j)]/19 = [(17.0 -4.0)i - (-1.0 -1.0)j]/19 = (13.0i - 2.0j)/19 = 0.68i - 0.11j m/s²

The horizontal component of acceleration a₁ = 0.68 m/s²

The vertical component of acceleration a₂ = -0.11 m/s²

b. The direction of the acceleration relative to the unit vector i,

tanθ = a₂/a₁ = -0.11/0.68 = -0.1618

θ = tan⁻¹(-0.1618) = -9.19° ⇒ 360 + (-9.19) = 350.81° from the the positive x-axis

6 0
3 years ago
How to make an uncharged particle positively charged
AlekseyPX

Answer:

If a neutral atom gains electrons, then it will become negatively charged. If a neutral atom loses electrons, then it become positively charged.

6 0
3 years ago
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