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umka21 [38]
3 years ago
7

How would having too much sample in the melting point tube most likely affect the melting point measurement? Select the correct

answer?
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

2-4 mm height of capillary tube.

Explanation:

Sample should be around 2-4 mm in height.

It should be packed well so that it does not have air packets that caues the lowering of melting point.

If you take greater amount, then there will be needed more heat, resulting a wide range of melting point.

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Fynjy0 [20]

Answer:

D

Explanation:

8 0
3 years ago
How is conductivity related to pH?​
timama [110]

Answer:

Strongly acidic [or strongly basic] solution will have high conductivity.

Explanation:

3 0
3 years ago
Read 2 more answers
What would the products be for the reaction between Na3PO4 + MgSO4?
ivann1987 [24]

MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2

Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2

Explanation:

7 0
2 years ago
What is the difference between a material having the chemical property of being flammable vs having the chemical property of bei
makkiz [27]

Answer:

Being flammable means it supports burning,e.g. Oxygen, but being combustible means burning itself too. e.g. Hydrogen.

Explanation:

Hope it helps!!

4 0
3 years ago
Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
MrRissso [65]

Answer:

6,97x10⁻³ gallons

Explanation:

pH is defined as:

pH = -log [H⁺]

Thus, you need to have, in the end:

10⁻⁷ = [H⁺]

And you have, in the first:

10^{-9,33} = [H⁺]

The volume of swimming pool is:

700'000 galllons ×\frac{3,78541 L}{1 gallon} = 2649787 L

Thus, the moles of H⁺ in the first and in the end are:

First:

10^{-9,33}mol/L × 2649787L = 1,24x10⁻³ moles

End:

10^{-7}mol/L × 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

0,26376moles*\frac{1L}{10moles}* \frac{1gallon}{3,78541L} =

<em>6,97x10⁻³ gallons</em>

<em></em>

I hope it helps!

7 0
3 years ago
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