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kotykmax [81]
3 years ago
15

When electromagnetic radiation is arranged to wavelength and frequency, it forms the

Physics
1 answer:
Lunna [17]3 years ago
4 0
A. electronic spectrum
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A pendulum is timed, first for 20 swings and then for
wlad13 [49]

w =  \frac{t(50) - t(20)}{50 - 20}  =  \frac{43.2 - 17.4}{50 - 20}

w =  \frac{25.8}{30}  = 0.86 \: sec \: per \: swing

The results may differ due to resistive forces that may be affecting the system by decelerating it or any other external forces that might accelerate it a bit.Or the timing could be a little inaccurate.

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2 years ago
The amount of energy in the universe is...
g100num [7]
The amount of energy in the universe is remaining constant .

So , option (D) is right ..

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3 years ago
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An electric heater,rated 15 volts 40 watts fitted into a metal block supplies heat to the block of mass 1.5kg and specific heat
Ghella [55]

The temperature rises of in the block if the current flows for 10 minutes is, 34.78K.

To find the answer, we need to know about the power of the electric heater.

<h3>How to find the temperature rise of in the block if the current flows for 10 minutes?</h3>
  • We have given with the variables,

                           P=40 W\\m=1.5kg\\S=460\\t=10minutes=10*60s=600s

  • We have an expression the heat given to the system as,

                             P*t= mSΔT

  • We have to find the temperature rise ΔT,

                           ΔT =\frac{P*t}{mS} =\frac{40*600}{1.5*460} =34.78K

Thus, we can conclude that, the temperature rises in the block if the current flows for 10 minute is 34.78K.

Learn more about the power of the electric heater here:

brainly.com/question/28050631

#SPJ1

7 0
2 years ago
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The gage pressure in a liquid at a depth of 3 m is read to be 50 kPa. Determine the gage pressure in the same liquid at a depth
Andrei [34K]

Answer:

The Gauge pressure at 9 meters depth is 150 \, kPa

Explanation:

Gauge pressure is the difference between absolute pressure and some reference pressure, most commonly atmospheric pressure. The increment in pressure caused by a static fluid is given by:

\Delta P = \rho g d where \rho is the density of the liquid,  g is the accleration due to gravity and d is the depth.

Now, we see that \Delta P is linearly proportional to d, and we can assume that \rho remains constant, because liquids are usually not compressible.

Given that the greater depth is simply 3 times the smaller depth:

d_2=3\cdot d_1\\9\,m= 3 \cdot 3\,m

\Delta P at 9\, m of depth will also be three times the gauge pressure at 3 \,m of depth.

We could also have calculated \rho ny using:

\Delta P = \rho \,g \,d\\\\\rho = \frac{\Delta P}{g \, d}\\\\\rho = \frac{\Delta P}{g \, d}= \frac{30 \,kPa}{9.8 \frac{m}{s^2}  \, 3\,m}=1020.41 \frac{kg}{m^3}

and used this result to calculate the gauge pressure. These are both similar methods that yield the same result

4 0
3 years ago
The even distribution of weight in a compostion is known as
mojhsa [17]
The answer is Balance. hopei helped? ahahahaha
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3 years ago
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