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svetoff [14.1K]
3 years ago
10

A survey team is trying to estimate the height of a mountain above a level plain. from one point on the plain, they observe that

the angle of elevation to the top of the mountain is 28 ∘ . from a point 1000 feet closer to the mountain along the plain, they find that the angle of elevation is 30 ∘ .

Physics
1 answer:
sweet-ann [11.9K]3 years ago
5 0

The height of the mountain is 11650 ft.

At the angle of 28 degree apply the tangent law

tan28=\frac{h}{x} Eq.1

At the angle of 30 degree apply the tangent law

tan30=\frac{h}{(x-1000)} Eq. (2)

On solving eq. (1) and Eq. (2)

The height of the mountain is h=11650 ft.

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kipiarov [429]

This question is incomplete, the complete question is;

A woman is 160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright.

Hint: Consider the ray diagram below, of the rays that enable her to see her feet and the top of her head.

Use what you know about the law of reflection, together with a bit geometry.

The missing Image is uploaded along this answer below.

Answer:

the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

Explanation:

Given the data in the question and illustrated in the image below,

From image 2;

The distance from the woman's eyes to the top of her head is represented as b and a represent the distance from her eyes to her feet.

Therefore, since her height is 160 cm

a + b = 160 ------ let this be equation 1

i.e AD + DG = 160 cm

Now, from the same image 2, we will notice that triangle ABC and tringle CBD are similar, so

∠ABC = ∠CBD

AC = CD

since AD = a and AC + CD = A

AC = CD = a/2

Also, triangle DEF and FEG are si,ilar

∠DEF = ∠FEG

so

DF = FG

since DG = b and DF + FG = b

DF = b/2

so the minimum vertical length of a mirror in which the woman can see her entire body while standing upright will be;

⇒ a/2 + b/2  

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from equation 1, a + b = 160

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⇒ a + b / 2 = 160 / 2 = 80

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