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svetoff [14.1K]
3 years ago
10

A survey team is trying to estimate the height of a mountain above a level plain. from one point on the plain, they observe that

the angle of elevation to the top of the mountain is 28 ∘ . from a point 1000 feet closer to the mountain along the plain, they find that the angle of elevation is 30 ∘ .

Physics
1 answer:
sweet-ann [11.9K]3 years ago
5 0

The height of the mountain is 11650 ft.

At the angle of 28 degree apply the tangent law

tan28=\frac{h}{x} Eq.1

At the angle of 30 degree apply the tangent law

tan30=\frac{h}{(x-1000)} Eq. (2)

On solving eq. (1) and Eq. (2)

The height of the mountain is h=11650 ft.

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Answer: Accoding to research "Triton is unique among all the large moons in the solar system because it orbits Neptune in a direction opposite to the planet's rotation (a "retrograde" orbit). It is unlikely to have formed in this configuration and was probably captured from elsewhere."

Explanation:

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What is the strategy you use to solve word problems in physics?
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A loop rests in the plane of a page of textbook while a magnetic field is directed into the page. A clockwise current is induced
Sunny_sXe [5.5K]

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When the magnetic field is tilted so it is no longer perpendicular to the page.

When the magnetic field gets stronger.

When the size of the loop decreases.

Explanation:

According to the Faraday-Lenz law, the change of the magnetic flux over time causes an induced current, this flux is given by:

\Phi_B=BScos\theta

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8 0
3 years ago
An iron railroad rail is 700 ft long when the temperature is 30°C. What is its length when the temperature is – 10°C?
MAVERICK [17]

Answer:

699.67ft

Explanation:

We are given with,

  • α = 1.2×10⁻⁵ / °C
  • L₀ = 700 ft
  • ΔT = -10°C − 30°C = -40°C

Now, We have to find ΔL:

  • ΔL = (1.2×10⁻⁵ / °C) (700 ft) (-40°C)
  • ΔL = −0.336

Rounded to two significant figures, the change in length is −0.33ft.

<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.

6 0
3 years ago
A planet's moon travels in an approximately circular orbit of radius 7.0 ✕ 10⁷ m with a period of 6 h 38 min. Calculate the mass
natka813 [3]

Answer:

3.56×10²⁶ Kg.

Explanation:

Note: The gravitational force is acting as the centripetal force.

Fg = Fc........................... Equation 1

Where Fg = gravitational Force, Fc = centripetal force.

Recall,

Fg = GMm/r²......................... Equation 2

Fc = mv²/r............................. Equation 3

Where M = mass of the planet, m = mass of the moon, r = radius of the orbit and G = Universal gravitational constant.

Substituting equation 2 and 3 into equation 1

GMm/r² = mv²/r

Simplifying the equation above,

M = v²r/G .............................. Equation 4.

The period of the moon in the orbit

T = 2πr/v

Making v the subject of the equation,

v = 2πr/T............................. Equation 5

where r = 7.0×10⁷ m, T = 6 h 38 min = (6×3600 + 38×60) s = (21600+2280) s

T = 23880 s, π = 3.14

v = (2×3.14×7.0×10⁷ )/23880

v = 18409 m/s

Also Given: G = 6.67×10⁻¹¹ Nm²/kg²

Also substituting into equation 4

M = 18409²×7.0×10⁷ /(6.67×10⁻¹¹)

M = 3.56×10²⁶ Kg.

Thus the mass of the planet =  3.56×10²⁶ Kg.

5 0
3 years ago
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