Non-polarized capacitors also referred to as ceramic capacitors or ac capacitors can be used on both ac and dc circuits.
A capacitor is an electronic device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to the amount of electric energy a capacitor can store. The capacity of a capacitor is measured in Farads (F).
AC and DC circuit is categorized as per the type of current that flows through the circuit. The direction of the current in alternating current alternates between moving forward and moving backwards. When in direct current, it consistently flows in a single direction.
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brainly.com/question/17176550
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Answer:
The answer is "
"
Explanation:
In this question, the halfway indicates the height that is ![\frac{28.8}{2}=14.4 \ m](https://tex.z-dn.net/?f=%5Cfrac%7B28.8%7D%7B2%7D%3D14.4%20%5C%20m)
Using formula:
![v^2=u^2+2as\\\\v^2=24^2+2(-10)(14.4)\\\\](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as%5C%5C%5C%5Cv%5E2%3D24%5E2%2B2%28-10%29%2814.4%29%5C%5C%5C%5C)
![v^2=576-288\\\\v^2=288\\\\v=\sqrt{288}\\\\v=16.97 \ \frac{m}{s}](https://tex.z-dn.net/?f=v%5E2%3D576-288%5C%5C%5C%5Cv%5E2%3D288%5C%5C%5C%5Cv%3D%5Csqrt%7B288%7D%5C%5C%5C%5Cv%3D16.97%20%5C%20%5Cfrac%7Bm%7D%7Bs%7D)
The air pressure is most likely lower.
Answer:
Net force needed to accelerate the skier is 136 N
Explanation:
As per Newton's 2nd law we know that net force on the system is product of mass and its acceleration
here we know that
m = 34 kg
![a = 4 m/s^2](https://tex.z-dn.net/?f=a%20%3D%204%20m%2Fs%5E2)
so we have
F = ma
![F = 34 \times 4](https://tex.z-dn.net/?f=F%20%3D%2034%20%5Ctimes%204)
![F = 136 N](https://tex.z-dn.net/?f=F%20%3D%20136%20N)
Answer
given,
length of slender rod =80 cm = 0.8 m
mass of rod = 0.39 Kg
mass of small sphere = 0.0200 kg
mass of another sphere weld = 0.0500 Kg
calculating the moment of inertia of the system
![I = \dfrac{ML^2}{12}+\dfrac{m_1L^2}{4}+\dfrac{mL^2}{4}](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7BML%5E2%7D%7B12%7D%2B%5Cdfrac%7Bm_1L%5E2%7D%7B4%7D%2B%5Cdfrac%7BmL%5E2%7D%7B4%7D)
![I = \dfrac{0.39\times 0.8^2}{12}+\dfrac{0.02\times 0.8^2}{4}+\dfrac{0.05\times 0.8^2}{4}](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B0.39%5Ctimes%200.8%5E2%7D%7B12%7D%2B%5Cdfrac%7B0.02%5Ctimes%200.8%5E2%7D%7B4%7D%2B%5Cdfrac%7B0.05%5Ctimes%200.8%5E2%7D%7B4%7D)
![I =0.032\ kg.m^2](https://tex.z-dn.net/?f=I%20%3D0.032%5C%20kg.m%5E2)
using conservation of energy
![\dfrac{1}{2}I\omega^2 = (m_1-m_2)g\dfrac{L}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7DI%5Comega%5E2%20%3D%20%28m_1-m_2%29g%5Cdfrac%7BL%7D%7B2%7D)
![\omega=\sqrt{\dfrac{(m_1-m_2)gL}{I}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7B%28m_1-m_2%29gL%7D%7BI%7D%7D)
![\omega=\sqrt{\dfrac{(0.05-0.02)\times 9.8 \times 0.8}{0.032}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7B%280.05-0.02%29%5Ctimes%209.8%20%5Ctimes%200.8%7D%7B0.032%7D%7D)
![\omega=2.71 \rad/s](https://tex.z-dn.net/?f=%5Comega%3D2.71%20%5Crad%2Fs)
we know,
v = r ω
![v = \dfrac{L}{2} \times 2.71](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7BL%7D%7B2%7D%20%5Ctimes%202.71)
![v = \dfrac{0.8}{2} \times 2.71](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B0.8%7D%7B2%7D%20%5Ctimes%202.71)
v = 1.084 m/s