Answer:
a) 
b) 
c) Q = 1.256 × 10⁻³ m³/s
Explanation:
Given:
The velocity profile as:

Now, the maximum velocity of the flow is obtained at the center of the pipe
i.e r = 0
thus,

or

Now,

or

or

Now, the flow rate is given as:
Q = Area of cross-section of pipe × 
or
Q = 
or
Q = 
or
Q = 1.256 × 10⁻³ m³/s
Answer:
the correct answer is D.) 2,4
The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:
Using the Velocity Hourly Equation, we get:
Uniting the equations:
Entering the unknowns:

Obs: Approximate results
If you notice any mistake in my english, please let me know, because i am not native.
Answer:
U = - 4 x 
Explanation:
ΔV = potential difference =
Volts
q = charge on electron =
C
electric potential energy is given as
U = q ΔV = (
) (
)
= - 4 x 
<span>AS T1,T2,T3 are the tensions in the ropes,assuming that there are Three blocks of mass 3m, 2m, and m.T3 is the string between 3m and 2m,T2 is the string between 2m and m ,T1 is the string attached to m thus T1 pulls the whole set of blocks along, so it must be the largest. T2 pulls the last
two masses, but T3 only pulls the last mass, so T3 < T2 < T1.</span>