Auhmm, ms/mr. your question was too blurry
Explanation:
plss can u kinda repost it?
Answer:
Explanation:
Given
mass of Projectile(m)=0.46 kg
Initial Kinetic Energy=1430 J
Maximum upward displacement from Launch point=150 m


v=78.85 m/s
and 



initial horizontal velocity

Initial vertical velocity


(c)vertical velocity at any instant=65 m/s
Since initial vertical velocity is 54.16 m/s
so 65 m/s will be acquired when projectile started falling below cliff



<span>It separates the metals from the non metals</span>
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.
The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.
v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s
Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.
The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.
Combining this together we get:
(1) vx=40m/s and vy=10m/s
Answer:
0.11 kg
Explanation:
Ft = MV
Ft = momentum 5.22kg m/s
M = mass
V = velocity 48.3m/s
Therefore
5.22 = M x 48.3
Divide both sides by 48.3
5.22/48.3 = M x 48.3/48.3
0.11 = M
M = 0.11kg