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egoroff_w [7]
3 years ago
13

What is the rate of acceleration of 2000 kilogram truck if a force of 4200 n is used to make it start moving forward

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
8 0
<h3>Answer:</h3>

                 2.1 m.s⁻²

<h3>Solution:</h3>

Data Given:

                  Force  =  4200 N  =  4200 Kg.m.s⁻²

                  Mass  =  2000 Kg

                  Acceleration  =  ??

Formula Used;

                  Force  =  Mass × Acceleration

Solving for Acceleration,

                  Acceleration  =  Force ÷ Mass

Putting values,

                  Acceleration  =  4200 Kg.m.s⁻² ÷ 2000 Kg

                  Acceleration  = 2.1 m.s⁻²

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0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

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