Answer:
how matter and energy interact
Answer:
Induced emf,
Explanation:
It is given that,
Rate of change of magnetic field,
A UHF antenna is oriented at an angle of 47° to a magnetic field, θ = 47°
Diameter of the antenna, d = 13.4 cm
Radius, r = 6.7 m = 0.067 m
We need to find the induced emf of the antenna. It is given by :
Where
= magnetic flux,
So,
B = magnetic field
So, the induced emf of the antenna is 2.2 mV. Hence, this is the required solution.
centre of square disrance to each corner found by Pythagoras' theorem.
coulombs law used to clculate field of each charge at centre
fields added vectorially for res
Answer:
Explanation:
Given data
Length L=2.5 m
Radius R=d/2=30/2 = 15 mm
Torque based on allowable stress
Allowable shear stress τ=50 Mpa
Allowable torque T=(π/2)τc³
Torque based on allowable angle of twist
Allowable Angle of twist
Ф=7.5°
Ф=7.5×(π/180)=130.90×10⁻³ rad
Allowable torque
T=(GJФ)/L
T=(G(π/2)c⁴)Ф)/L
T=(πGc⁴Ф)/2
Maximum Power Transmitted
Maximum power transmitted is given by
In order to find the radius of the coin, we need to use:
Ac = V^2 r
In which,
Ac = acceleration of the coin = 2.2 m/s^2
V= rotational Speed = (18/12) * 2πr
r= Radius
so,
<span>2.2 = 9(π^2)(r^2) / r
</span><span>= 9(π^2)r
</span>
<span>r = 2.2 / 9(π^2) = 0.02476740044 m . . .or you can rounded it up to 0.025 m</span>