Question

The path of a ball kicked from the ground can be modeled by the equation y=−1/4(x−2)(x−22), where x and y are measured in feet. The x-axis represents the ground. How far does the ball land from where it is kicked? The ball lands feet from where it is kicked.

Answer 1

Answer:

The ball land 20 feet away from where it is kicked.

Step-by-step explanation:

The path of a ball kicked from the ground can be modeled by the equation:

$y=-\frac{1}{4}(x-2)(x-22)$

Where x represents the ground.

Substitute y= 0

So,$0=-\frac{1}{4}(x-2)(x-22)$

$(x-2)(x-22)=0$

$x=2,22$

So, Distance covered by ball = 22-2=20

So, The ball land 20 feet away from where it is kicked.