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anygoal [31]
4 years ago
8

A certain car going from Atlanta to Philadelphia averages 24.0 m/s over the course of the trip. Determine how long it takes the

car to reach Philadelphia if 1,250 km away from atlanta by road. Report your answer in hours. (Be careful of units!)
Physics
1 answer:
Dennis_Churaev [7]4 years ago
6 0

Answer:

14.5 hours

Explanation:

The relationship between speed, time and distance for a uniform motion is

v=\frac{d}{t}

where

v is the speed

d is the distance

t is the time taken

Here we know:

v = 24.0 m/s is the average speed

d=1250 km = 1.25\cdot 10^6 m is the distance

Solving the equation, we find the time taken:

t=\frac{d}{v}=\frac{1.25\cdot 10^6 m}{24.0 m/s}=52083 s

And since

1 hour = 3600 s

The time in hours is

t=52083 s \cdot \frac{1}{3600 s}=14.5 h

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Explanation:

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A high-speed flywheel in a motor is spinning at 450 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and
alexira [117]

Answer:

A) \omega_f=17.503\ rad.s^{-1}

B) t=55.6822\ s

C) \theta=1312\ rad

Explanation:

Given:

  • mass of flywheel, m=40\ kg
  • diameter of flywheel, d=0.72\ m
  • rotational speed of flywheel, N_i=450\ rpm \Rightarrow \omega_i=\frac{450\times 2\pi}{60} =15\pi\ rad.s^{-1}
  • duration for which the power is off, t_0=35\ s
  • no. of revolutions made during the power is off, \theta=180\times 2\pi=360\pi\ rad

<u>Using equation of motion:</u>

\theta=\omega_i.t+\frac{1}{2} \alpha.t^2

360\pi=15\pi\times 35+\frac{1}{2} \times \alpha\times35^2

\alpha=-0.8463\ rad.s^{-2}

Negative sign denotes deceleration.

A)

Now using the equation:

\omega_f=\omega_i+\alpha.t

\omega_f=15\pi-0.8463\times 35

\omega_f=17.503\ rad.s^{-1} is the angular velocity of the flywheel when the power comes back.

B)

Here:

\omega_f=0\ rad.s^{-1}

Now using the equation:

\omega_f=\omega_i+\alpha.t

0=15\pi-0.8463\times t

t=55.6822\ s is the time after which the flywheel stops.

C)

Using the equation of motion:

\theta=\omega_i.t+\frac{1}{2} \alpha.t^2

\theta=15\pi\times 55.68225-0.5\times 0.8463\times 55.68225^2

\theta=1312\ rad revolutions are made before stopping.

3 0
3 years ago
Acceleration is rate of change of <br>A-Position<br>B-Time<br>C-Velocity<br>D-Speed​
Drupady [299]
<h3>Answer:</h3>

[C] Velocity.

<h3>Explanation:</h3>

<u>As we know that</u>,

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<u>where, a = acceleration, v = final velocity, u = initial velocity and t = time taken to travel</u>.

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