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Luden [163]
3 years ago
15

Define not matter and give examples​

Chemistry
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

Everything that has mass and takes up space is matter. Every day, you encounter phenomena that either don't have mass or don't take up space. They are non-matter. Basically, any type of energy or any abstract concept is an example of something that is not matter.

An apple.

A person.

A table.

Air.

Water.

A computer.

Paper.

Iron.

hope this helped you

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zloy xaker [14]

Answer: 3M

Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute KOH = 0.6 moles

V_s = volume of solution in ml= 200 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.6moles\times 1000}{200ml}=3mole/L

Therefore, the molarity of solution will be 3M.

8 0
3 years ago
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How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmat
stira [4]

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

8 0
3 years ago
What is the mass of 3.95 l of methane gas at 0.870 atm and 35.0 degrees celsius?
dalvyx [7]

Answer:

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PV = nRT       n = number of moles

                       R = gas constant = .082057 L-atm/(K-mol)

                           T must be in units of K

.870 (3.95) = n (.082057)(35+273.15)    

   solve for n = .1359 moles

Methane mole weight (CH4) = 16 gm / mole

.1359 moles  *  16 gm/mole = 2.174 gm

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ololo11 [35]

Answer:

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andreev551 [17]

Heat is released.

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