Answer:
root-mean-sqaure = 2.77 m/s
average = 2.72 m/s
The root-mean-square is always the largest because it takes account of the variance of the spread of the data. The increase is related to the fact that the data varies to sample.
Explanation:
The rootmean-square (R) is the square root of the squares of the valeus divided by the number of the datas.
R = √(46.03)/6
R = 2.77 m/s
The average speed is the sum of the speeds divided by the number of datas:
A = 16.3/6
A = 2.72 m/s
Answer:
Explanation:
Hello,
In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:
Next, for the given energy, we compute the total heat that is liberated:
Finally, we conclude such symbol has sense since negative heat is related with liberated heat.
Best regards.
Answer:
Well we know that matter is neither created nor destroyed by chemical reactions or physical transformations. It is not destroyed it simply was converted to gas. =D
Answer:
the water concentration at equilibrium is
⇒ [ H2O(g) ] = 0.0510 mol/L
Explanation:
- CH4(g) + H2O(g) ↔ CO(g) + 3H2(g)
∴ Kc = ( [ CO(g) ] * [ H2 ]³ ) / ( [ CH4(g) ] * [ H2O(g) ] ) = 0,30
⇒ [ CO(g) ] = 0.206 mol / 0.778 L = 0.2648 mol/L
⇒ [ H2(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L
⇒ [ CH4(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L
replacing in Kc:
⇒ ((0.2648) * (0.2404)³) / ([ H2O(g) ] * 0.2404 ) = 0.30
⇒ 0.0721 [ H2O(g) ] = 3.679 E-3
⇒ [ H2O(g) ] = 0.0510 mol/L
