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3 years ago

Which of the following statements is true?

Physics

2 answers:

azamat3 years ago

7 0

Answer:

Water vapor helps keep the earth's heat from escaping into space.

Explanation:

Of all the options only the first option is correct. Yes, the water vapor helps keep the Earth's heat from escaping into the space. Water vapor is green house gas meaning it has the ability to absorb heating coming from the sun. Among the rest options sublimation is process of conversion of solid directly into the gas. Most of the water vapor in the air does not come from the transpiration and evaporation from the oceans add salt water to the atmosphere is absolutely wrong.

belka [17]3 years ago

6 0

The first option is true, water vapor helps keep the Earth's heat from escaping into space.

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a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed

Juliette [100K]

Mass of the car (m) = 2000 Kg
Initial velocity (u) = 15 m/s
Force (F) = 10000 N
Time (t) = 3 s
Let the acceleration be a.
By using the formula, F = ma, we get,
10000 N = 2000 Kg × a
or, a = 10000 N ÷ 2000 Kg
or, a = 5 m/s^2
Let the final velocity be v.
By using the formula, v = u + at, we get,
v = 15 m/s + 5 m/s^2 × 3 s
or, v = 15 m/s + 15 m/s
or, v = 30 m/s

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

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3 years ago

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Sergio [31]

Answer:

(a) To draw water from a well we have to pull at the rope.

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Explanation:

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3 years ago

A car is travelling with a velocity of 10 m/s and has a mass of 550 kg. The car has energy.

Elenna [48]

Answer: The car has a kinetic energy (because it's in motion) of: $27500J$

Explanation:

$Formula: E=\frac{1}{2}mv^2$

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}(550kg)(10m/s)^2$

$E=\frac{1}{2}(550kg)(100m^2/s^2)$

$E=\frac{1}{2}(55000J)\\E=27500J$

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3 years ago

Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?

Schach [20]

Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.

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3 years ago

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Basile [38]

Saying english so we can help u

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