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Artemon [7]
3 years ago
10

The 6kg box is pushed to the left at a constant speed. The coefficient of friction is 0.78. Solve for the amount of force with w

hich the hand pushes the box.
Physics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

45.864N

Explanation:

Using the formula

F = nR

n is the coefficient of friction

R is the normal reaction

R = mg

F = nmg

F = 0.78 * 6 * 9.8

F = 45.864N

Hence the amount of force with which the hand pushes the box is 45.864N

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Stells [14]

Answer:

D

Explanation:

Let’s calculate the kinetic energy for all of the choices.

a. (1/2)(100)(100)^2 = 50(10000)=500,000

b. (1/2)(100)(1)^2 = 50

c. (1/2)(10)(100)^2 = 5(10000) = 50,000

d. (1/2)(1)(1)^2 = 0.5

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5 0
2 years ago
Describe briefly how you would check that the rule is horizontal in this experiment. You  may draw a diagram.​
aliina [53]

Answer:

We want to describe how to graph a linear equation.

Explanation:

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To get the points, we just need to evaluate the function in two different values of x.

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pls give brainliest!

3 0
2 years ago
wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate
liq [111]

Answer:

V = 152.542 volts

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