Question

What volume (in mLs) of 1.50 M Na2CO3 solution can be prepared from 3.975 g of solid Na2CO3?

Answer 1

Answer:

56.25 mL

Explanation:

We are given;

Molarity of Na₂CO₃ = 1.50 M

Mass of Na₂CO₃ = 3.975 g

We are required to calculate the volume of Na₂CO₃

Step by step explanation:

Step 1: Determining moles of Na₂CO₃

Molar mass of Na₂CO₃ = 106 g/mol

But; moles = Mass ÷ molar mass

Therefore;

Moles of Na₂CO₃ = 3.975 g ÷ 106 g/mol

                             = 0.0375 moles

Step 2: Calculating the volume of Na₂CO₃

Relationship between volume, moles and molarity is given by;

Molarity = Moles ÷ Volume

Thus;

Volume = moles ÷ Molarity

             = 0.0375 mole × 1.5 M

             = 0.05625 L

But; 1 L = 1000 mL

Therefore; Volume = 56.25 mL

Hence, the volume of Na₂CO₃ is 56.25 mL