Answer:
See below
Explanation:
From periodic table, find Mole Weight of the element in question
this is the grams of the element in Avagadro's Number (6.022 x 10^23) of atoms
(5.50 x 10^22) / (6.022 x 10^23) x mole weight = grams
Answer is: mass od zinc is 392,28 g.
N(Zn) = 3,6·10²⁴.
n(Zn) = N(Zn) ÷ Na.
n(Zn) = 3,6·10²⁴ ÷ 6·10²³ 1/mol.
n(Zn) = 6 mol.
m(Zn) = n(Zn) · M(Zn).
m(Zn) = 6 mol · 65,38 g/mol.
m(Zn) = 392,28 g.
Na - Avogadro number.
n - amount of substance.
M - molar mass.
The answer is (2) 0.2. The unit of M means 1 mol/L. The conversion of liter and milliliter is 1 liter equals 1000 milliliters. So the molar number of solute is 1*0.2=0.2 mol.
Answer:
4.083 * 10^20 atoms.
Explanation:
One Mole of phosphorus contains 6.022 * 10^23 atoms (Avogadros number)'
Since 1 mole of Phosphorus has a mass of 30.974 grams, 21 milligrams has
6.022 * 10^23 * 0.021 / 30.974
= 0.004083 * 10^23
= 4.083 * 10^20
