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3 years ago

What is the hybridization of the central atom in NOCl

Chemistry

1 answer:

FinnZ [79.3K]3 years ago

3 0

Answer:

NOCl structure has geometry of trigonal planar and N has sp2 hybridisation. N is the central atom because it is less electronegative than O atom and Cl cannot be the central atom because it only forms a single bond. So, the central atom of NOCl is N and its hybridisation

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Write insoluble or soluble solution for the following mixtores 1 2 3 4 5

dimaraw [331]

Gasoline in water = insoluble

acetone in nail polished = soluble

salt in alcohol = soluble

oil in vinegar = insoluble

tawas in water = soluble...

Sorry if i am incorrect......

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2 years ago

Which explains how burning a magnesium ribbon highlights a toolmark?

Setler [38]

<h2>Answer:</h2>

The magnesium ribbon, D. It forms a material to cast the tool mark.

<h2>Explanation:</h2>

When a magnesium ribbon is burnt in the presence of oxygen it gives out strong light and heat is produced. Apart from it, it leads to the production of substance called as magnesium oxide which is formed as the product due to the reaction of magnesium with the oxygen present in the air.

Tool marks are the mark which is created by tools while using them. In order to identify or locate them castes made up of magnesium oxide is utilized. When this is pasted on the suspected area, the tool mark of the suspected tool gets pasted on it.

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4 years ago

A mineral consisted of 29.4% calcium, 23.5% sulfur and 47.1% oxygen. What is the empirical formula?

inessss [21]

Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol

moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles

calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
therefore the emipical formula = CaSO4

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3 years ago

How many molecules are present in 4.5 moles of H2O?

Gekata [30.6K]

Answer:

Mole of the H2O = 4.5

Number of molecules =4.5 multipled by avogadro's number.

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3 years ago

Arrange the steps of glycogen degradation in their proper order. Hormonal signals trigger glycogen breakdown. Glucose 6‑phosphat

Otrada [13]

Answer: Please see answer below

Explanation:

The steps of glycogen degradation is as follows from this order.

--->Hormonal signals trigger glycogen breakdown.

1. Glycogen is (de)branched by hydrolysis of α‑1,6‑glycosidic linkages.

2. Blocks consisting of three glucosyl residues are moved by remodeling of α‑1,4‑glycosidic linkages.

3.[Glucose 1‑phosphate is cleaved from the non reducing ends of glycogen and converted to glucose 6‑phosphate.

--->Glucose 6‑phosphate undergoes further metabolic processing

The degradation of Glycogen follows three steps:

(1) the release of glucose 1-phosphate from glycogen,

(2) the remodeling of the glycogen substrate to permit further degradation, and

(3) the conversion of glucose 1-phosphate into glucose 6-phosphate for further metabolism.

(https://www.ncbi.nlm.nih.gov/books/NBK21190)

4 0

3 years ago