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Arturiano [62]
3 years ago
7

At the instant that the velocity of the crate is v⃗ =(3.40m/s)ι^+(2.20m/s)j^, what is the instantaneous power supplied by this f

orce?
Physics
1 answer:
Zigmanuir [339]3 years ago
5 0
I found some missing information about this problem online. We are given the force:
F = F =(-7.50N)i +(3.00N)j
Power is defined as the rate of doing work. 
This is the formula:
P= \frac{dW}{dt}
Where P is power, W is work. 
Work is defined as:
W=F\cdot r
F is the force and r is the displacement.
If we assume that force is not changing (it's constant) with time we get:
P= \frac{dW}{dt}=F \frac{dr}{dt}=F\cdot v
Keep in mind that both force and velocity are vectors, so we have to multiply each component separately.
Finally, we get:
P=F_i\cdot v_i+F_j\cdot v_j=(-7.50N)(3.40\frac{m}{s})+(3.00N)(2.20\frac{m}{s})=
-18.9 W


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