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3 years ago

Why are weight and mass used synonymously on Earth?

Chemistry

2 answers:

sasho [114]3 years ago

6 0

The difference between mass and time is the influence of the earth's gravitational force on objects

<h3><em>Further explanation</em></h3>

In general, some people equate mass and weight.

Mass is one of the principal quantities, which is related to the matter in the matter, whereas weight is a force that leads to the center of the earth which is subject to the earth to matter (Earth's gravitational force)

So that the mass does not depend on the location of the object, while the weight can change depending on the position of the object

In international standards, the mass unit is kg while the weight is in units of newton

1 kg itself is the mass of a cylinder made of platinum-iridium

While the standard mass of an atom is determined according to the carbon-12 atomic mass of 12 atomic mass units

1 atomic mass unit comparable to 1.6605402.10-17 kg

Measuring the atomic mass using a mass spectrometer.

The mass itself can be measured by the arm balance while the weight is measured by the spring balance

One equation that can relate mass and force (weight) is

W = m.g

W = weight, N

m = mass, kg

g = gravity acceleration, m / s2

<h3><em>Learn more</em></h3>

statements can be made about mass and weight

brainly.com/question/2976693

weight on Earth and moon

brainly.com/question/3908593

units are used to measure mass and weight

brainly.com/question/1440987

Keywords: mass, weight, gravity

RUDIKE [14]3 years ago

5 0

Actually mass and weight are two different things but most people did not understand the difference between them. And they are used synonymously on the earth. Mass is the measure of the amount of matter and weight is the measure of how the force of gravity acts on the mass that is Weight = mass x force of gravity. And they are also directly proportional to each other that is also the reason both terms are used synonymously.

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3 years ago

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How many liters of 1.75 M solution could be made using 35 grams of NaCl?

dolphi86 [110]

Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
$M = \frac{m}{MM*V}$

Solving:
$M = \frac{m}{MM*V}$
$1.75 = \frac{35}{58.44*V}$
$1.75*58.44V = 35$
$102.27V = 35$
$V = \frac{35}{102.27}$
$\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark$

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3 years ago

Snape grows tired of these conceptual questions and thinks it's time for a problem. What is the retention factor if the distance

MAVERICK [17]

Answer:

The Retention factor (rf) value is = 0.2

Explanation:

Retention factor (Rf) is factor used substances that could be separated using Chromatography. Retention factor determines how fast the component can move on the chromatogram (stationary phase) after elution. Elution occurs when mobile phase (solvent) moves across the stationary phase when the solute has been spotted on the origin.

Retention factor (Rf) ranges from value between 0 and 1. The closer the value to 1, the faster it can move upon elution. Rf can be calculated.

Rf value = distance moved by the solute / distance moved by the solvent

= 0.40cm / 2.00cm

= 0.2

6 0

3 years ago

A student made an initial 1:5 dilution of protein lysate. Then 2mL of that was added to 8mL of water. Lastly, the student made a

Licemer1 [7]

Answer:

The final dilution is 1:400

Explanation:

Let's analyze what we are told: we have an initial 1:5 dilution of protein lysate. This means that the initial solution (stock solution) was diluted 5 times. Then, from this dilution the student prepared another dilution taking 2 mL of the first dilution in 8 mL of water. This is the same as saying we took 1 mL of first dilution in 4 mL of water (the ratio is the same), so we now have a second 1:4 dilution of the first dilution (1:5). Finally, the student made a third 1:20 dilution, this means that the second dilution was further diluted 20 times.

So, to calculate the final dilution of protein lysate, we have to multiply all the dilution factors of every dilution prepared: in this case we have a final dilution of 1:20, this means we have a factor dilution of 20. But it was previously diluted 4 times, so we have a factor dilution of 20×4 = 80. However, this dilution was also previously diluted 5 times, so the new dilution factor is 80 × 5 = 400

This means that the final dilution of the compound was diluted a total of 400 times compared to the initial concentration of stock solution.

3 0

3 years ago

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

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3 years ago