PH=5.57
pH+pOH=14
5.57 + pOH=14
pOH = 14-5.57= 8.43
pOH = - log [OH⁻]
-pOH= log [OH⁻]
![[OH^{-}] = 10^{-pOH}= 10^{-8.43}= 3.72*10^{-9} [OH^{-}]= 3.72*10^{-9}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%2010%5E%7B-pOH%7D%3D%2010%5E%7B-8.43%7D%3D%203.72%2A10%5E%7B-9%7D%0A%0A%20%5BOH%5E%7B-%7D%5D%3D%203.72%2A10%5E%7B-9%7D)
pH+pOH=14
5.57 + pOH=14
pOH = 14-5.57= 8.43
pOH = - log [OH⁻]
-pOH= log [OH⁻]
A beaker with water and the surrounding air are all at 24°C. After ice cubes are placed in the water, heat is transferred from:
2 answers:
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Answer:
75.15 g/mol
Explanation:
First, let us look at the equation of reaction;
From the balanced equation of reaction, 1 mole of NaOH is required to completely neutralize 1 mole of HAA.
Recall that: mole = molarity x volume.
Therefore, 27.50 mL, 0.120 M NaOH = 0.0275 x 0.120 = 0.0033 moles
0.0033 mole of NaOH will therefore requires 0.0033 moles of HAA for complete neutralization.
In order to find the molar mass of the unknown amino acid, recall that:
<em>mole = mass/molar mass</em>, hence, <em>molar mass = mass/mole</em>.
Therefore, molar mass of HAA = 0.248/0.0033 = 75.15 g/mol