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Zina [86]
3 years ago
9

Visualize five horizontal sedimentary strata exposed in a cliff or canyon wall identified by consecutive numbers, 1 being the lo

west bed and 5 being the highest. Which of the following statements concerning the strata are true?
a. Bed 4 is older than bed 2.
b. Bed 3 is older than beds 2 and 4.
c. Bed 5 is the oldest.
d. Beds l and 3 are older than bed 4.
Physics
2 answers:
Grace [21]3 years ago
6 0

Answer:

Only the 4 th statement is true that is bed 1 and 3 are older than 4.

Explanation:

The 5 beds are numbered from 1 to 5 , 1 being the lowest and 5 being the topmost bed.

We are given 4 statements and we have to find out which all are true.

(<u>a)Bed 4 is older than bed 2 </u>

This is wrong because the lower beds are older than beds that are higher.

<u>(b)Bed 3 is older than beds 2 and 4</u>

This is also wrong because the 2 is older than 3

(<u>c)Bed 5 is the oldest </u>

This is wrong because bed 1 is the oldest

(<u>d)Beds 1 and 3 are older than 4</u>

This is true as lower beds are older

<u />

Vlad1618 [11]3 years ago
4 0

Answer:

bed 2 was deposited before bed 3

Explanation:

Which of the following conclusions can be made about the sedimentary layers?

bed 2 was deposited after bed 3

bed 1 is the youngest

bed 3 was deposited before bed 1

bed 2 was deposited before bed 3

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3 years ago
Twice a year the Sun’s rays strike Earth north or south of the....
solong [7]

Answer:

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Explanation:

4 0
3 years ago
A car with mass 1600 kg drives around a flat circular track of radius 28.0 m. The coefficient of friction between the car tires
egoroff_w [7]

Answer:

v=15.24 m/s

Explanation:

Given that

Mass ,m= 1600 kg

radius ,r= 28 m

Coefficient of friction ,μ = 0.83

The radial force on the car when it takes turn

F=\dfrac{mv^2}{r}

The friction force on the car

Fr= μ m g

The condition for motion without losing traction

F= Fr

\dfrac{mv^2}{r}=\mu\ m g

v²=μ r g

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Answer:

moment of inertia I ≈ 4.0 x 10⁻³ kg.m²

Explanation:

given

point masses = 50g = 0.050kg

note: m₁=m₂=m₃=m₄=50g = 0.050kg

distance, r, from masses to eachother = 20cm = 0.20m

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remember, a square will have 4 equal points

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I =  3.92 x 10⁻³ kg.m²

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attached is the diagram of the equation

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