3 years ago

A house that was heated by electric resistance heaters consumed 1500 kWh of electric

Engineering

1 answer:

gladu [14]3 years ago

5 0

Answer:

2.5=1500/Whp=> Whp=600 kWh

delWgain=1500-600=900 kWh

Money saved= 900* 6tk*=5400 tk

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