An object accelerates uniformly from 3.0 m/s east to 8.0 m/s east in 2.0 seconds. What is the magnitude of the acceleration of t
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Answer:
Explanation:
a. Internal energy and the relative specific volume at are determined from A-17:
.
The relative specific volume at is calculated from the compression ratio:
#from this, the temperature and enthalpy at state 2, can be determined using interpolations
and
. The specific volume at
can then be determined as:
Specific volume,:
The pressures at is:
.The thermal efficiency=> maximum temperature at can be obtained from the expansion work at constant pressure during
b.Relative SV and enthalpy at are obtained for the given temperature with interpolation with data from A-17 :
Relative SV at is
=
Thermal efficiency occurs when the heat loss is equal to the internal energy decrease and heat gain equal to enthalpy increase;
Hence, the thermal efficiency is 0.563
c. The mean relative pressure is calculated from its standard definition:
Hence, the mean effective relative pressure is 674.95kPa
Refer to the diagram shown below.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.