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3 years ago

A stationary 90 kg baseball pitcher throws a 0.15 kg baseball forward

Physics

1 answer:

Marina CMI [18]3 years ago

4 0

Answer: momentum = 6kgm/s

Explanation:

given that the baseball pitcher is at stationary position, his velocity will be equal to zero. If velocity is zero, his linear momentum will therefore equal to zero.

Linear momentum is the product of mass and velocity. Given that the baseball has

Mass M = 0.15 kg

Velocity V = 40 m/s

Momentum = MV

Momentum = 0.15 × 40 = 6 kgm/s

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3. Why does any bonding occur (this includes ionic bonding and covalent bonding)?

Rzqust [24]

Answer:im not sure but hope this helps

Explanation:

Covalent bonds are formed because of sharing electrons whereas ionic bonds formation occurs because of transferring of electrons. Molecules are the particles in covalent bonds all through compound formation whereas in ionic bonds these are positively charged and negatively charged ions.

6 0

3 years ago

You want to examine the hairy details of your favorite pet caterpillar, using a lens of focal length 8.9 cm 8.9 cm that you just

Zepler [3.9K]

Answer:

The angular magnification is $M = 2.808$

Explanation:

From the question we are told

The focal length is $f = 8.9cm$

The near point is $n_p = 25.0cm$

The angular magnification is mathematically represented as

$M = \frac{n_p}{f}$

Substituting values

$M = \frac{25}{8.9}$

$= 2.808$

4 0

3 years ago

Identify and explain the climate cycle shown

bazaltina [42]

Answer:

wnd change

Explanation: wnd chsnge

8 0

3 years ago

A power plant running at 31 % efficiency generates 270 MW of electric power. Part A At what rate (in MW) is heat energy exhauste

True [87]

Answer:

i did not learn this yet im going into 6th grade im still in 5th

i dont know

6 0

2 years ago

mass is 5 lb attached to a rope wound around a pulley. The radius of the pulley is 3 in. If the mass falls at a constant velocit

suter [353]

Answer:

The power transmitted to the pulley is 0.0455 hp.

Explanation:

Given;

mass attached to the rope, m = 5 lb

radius of the pulley, r = 3 in

constant rate of fall of the mass, v = 5 ft/s

acceleration due to gravity, g = 32.2 ft/s²

1 lbf = 32.2 lb.ft/s²

The power transmitted to the pulley is calculated as;

P = Fv

P = (mg)v

$P = 5 \ lb \ \times \ 32.2 \ \frac{ft}{s^2} \ \times \ 5 \ \frac{ft}{s} \ \times \ \frac{1 \ lbf}{32.2 \ lb.ft/s^2} \ \ = 25 \ \frac{ft.lbf}{s} \\\\$

in horse power, the power transmitted is calculated as;

$P = \frac{25 \ ft.lbf}{s} \ \times \ \frac{1 \ hp}{550 \ ft.lbf/s} \ \ = 0.0455 \ hp$

Therefore, the power transmitted to the pulley is 0.0455 hp.

3 0

2 years ago