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netineya [11]
3 years ago
9

A stationary 90 kg baseball pitcher throws a 0.15 kg baseball forward

Physics
1 answer:
Marina CMI [18]3 years ago
4 0

Answer: momentum = 6kgm/s

Explanation:

given that the baseball pitcher is at stationary position, his velocity will be equal to zero. If velocity is zero, his linear momentum will therefore equal to zero.

Linear momentum is the product of mass and velocity. Given that the baseball has

Mass M = 0.15 kg

Velocity V = 40 m/s

Momentum = MV

Momentum = 0.15 × 40 = 6 kgm/s

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"A capacitor charged to 1.5 V stores 2.0 mJ of energy. Determine the energy stored in the capacitor if it is charged to 3.0 V."
Salsk061 [2.6K]

To solve this problem we will apply the concepts related to electric potential energy. This relationship shows us that energy is equivalent to half the product between the capacitance of the body by the squared voltage. Mathematically it can be expressed as,

E = \frac{1}{2} CV^2

Here,

C = Capacitance

V = Voltage

E = Energy

The initial capacitance would then be given by

2mJ = \frac{1}{2} C (1.5)^2

C = \frac{4*10^{-3}}{(1.5)^2}

C = 1.78*10^{-3}F

Energy stored in the capacitor with 3V is

E = \frac{1}{2} (1.78*10^{-3})(3)^2

E = 8mJ

Therefore the energy stored in the capacitor if it is charged to 3V is 8mJ

8 0
3 years ago
If an object experiences an impulse and stops, what is its final momentum?
____ [38]

Answer:

Zero

Explanation:

Since momentum is a product of mass and velocity of an object, in this case when the object stops its final velocity is zero hence despite the magnitude of its mass, multiplied by zero the final momentum is equivalent to zero. However, in case after experiencing momentum its velocity reduces but doesn’t come to a rest, the momentum will have a value. For this question, the first case applies hence momentum value is zero.

3 0
3 years ago
Professional assessments are the only reliable method for determining an individual's levels of health-related fitness.
marin [14]

Answer:

True

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4 0
3 years ago
A race car starting from rest accelerates uniformly at 4.9 m/s^2. What is the car's speed after it has traveled 200 meters?
NeX [460]
The equation v²=u²+2as will help with solving this equation
v is what we are trying to find
u=0
a=4.9
s=200
v²=0²+2*4.9*200
v=√(2*4.9*200)
v=√1960
v=44.3 m/s (3 sf)
5 0
4 years ago
Read 2 more answers
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Ierofanga [76]
The answer is......2.54x10^-10......
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4 years ago
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