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3 years ago

Overlapping contour lines probably indicate a

Physics

1 answer:

lutik1710 [3]3 years ago

3 0

I'm not positive but I believe it is B. Overlapping contour lines probably indicate a cliff. :)

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6. Most organizations have not banned the use of performing enhancing drugs.

Setler79 [48]

The answer is false

4 0

3 years ago

The specific heat of water is 4.2 J/g • °C. How much heat is required to raise the temperature of 100 g of water by 5°C? *

Svetach [21]

Answer:

2100 J

Explanation:

The heat required to increase the temperature of a substance is given by

$Q=mC\Delta T$

where

m is the mass of the substance

C is its specific heat capacity

$\Delta T$ is its change in temperature

For the water in this problem, we have:

m = 100 g is its mass

C = 4.2 J/g • °C is the specific heat capacity

$\Delta T=5^{\circ}C$ is the increase in temperature

So, the amount of heat needed is:

$Q=(100)(4.2)(5)=2100 J$

7 0

3 years ago

What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n

Yuri [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The wavelength is $\lambda = 622 nm$

Explanation:

From the question we are told that

The distance of the slit to the screen is $D = 5 \ m$

The order of the fringe is m = 6

The distance between the slit is $d = 0.9 \ mm = 0.9 *10^{-3} \ m$

The fringe distance is $Y = 1.9 \ cm = 0.019 \ m$

Generally the for a dark fringe the fringe distance is mathematically represented as

$Y = \frac{[2m - 1 ] * \lambda * D }{2d}$

=> $\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}$

substituting values

=> $\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}$

=> $\lambda = 6.22 *10^{-7} \ m$

$\lambda = 622 nm$

8 0

3 years ago

When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic

alexandr1967 [171]

Coefficient of volume expansion is 8.1 ×10⁻⁴ C⁻¹.

<u>Explanation:</u>

The volume expansion of a liquid is given by ΔV,

ΔV = α V₀ ΔT

ΔT = change in temperature = 48.5° C

α = coefficient of volume expansion =?

V₀ = initial volume = 2.35 m³

We need to find α , by plugin the given values in the equation and by rearranging the equation as,

$\alpha=\frac{\Delta \mathrm{V}}{\mathrm{V}_{0} \Delta \mathrm{T}}=\frac{0.0920}{2.35 \times 48.5}=0.00081$

= 8.1 ×10⁻⁴ C⁻¹.

5 0

4 years ago

1: Why do the work of scientist cannot be pinned down to a single year?

zalisa [80]

It can't be pinned down to a single year because scientific work takes place over many years of research and discovery.

7 0

4 years ago