Overlapping contour lines probably indicate a

1. What is the primary difference between an ideal emf device and a real emf device? a) The electric potential of a real emf dev

Kazeer [188]

Answer:

The answer is option D.

Explanation:

An EMF device is a device that produces an electromagnetic field and the components that it has also have their own internal resistance.

This is the case in a real life EMF device but for an ideal EMF device, the internal resistance is equal to zero so there is no voltage drop because of that.

The answer is option D.

I hope this answer helps.

3 0

4 years ago

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles

miss Akunina [59]

Formula of the gravitational force between two particles:

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67 \cdot 10^{-11} Nm^2 kg^{-2}$ is the gravitational constant

m1 and m2 are the masses of the two particles

r is their distance

(a) particle A

The gravitational force exerted by particle B on particle A is

$F_B=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=5.14 \cdot 10^{-5} N$ to the right

The gravitational force exerted by particle C on particle A is

$F_C=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=5.6 \cdot 10^{-6} N$ to the right

So the net gravitational force on particle A is

$F_A = F_B + F_C =5.14 \cdot 10^{-5} N+5.6 \cdot 10^{-6} N=5.7 \cdot 10^{-5} N$ to the right

(b) Particle B

The gravitational force exerted by particle A on particle B is

$F_A=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=-5.14 \cdot 10^{-5} N$ to the left

The gravitational force exerted by particle C on particle B is

$F_C=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=8.41 \cdot 10^{-5} N$ to the right

So the net gravitational force on particle B is

$F_B = F_A + F_C =-5.14 \cdot 10^{-5} N+8.41 \cdot 10^{-5} N=3.27 \cdot 10^{-5} N$ to the right

(c) Particle C

The gravitational force exerted by particle A on particle C is

$F_A=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=-5.6 \cdot 10^{-6} N$ to the left

The gravitational force exerted by particle B on particle C is

$F_B=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=-8.41 \cdot 10^{-5} N$ to the left

So the net gravitational force on particle C is

$F_C = F_B + F_A =-8.41 \cdot 10^{-5} N-5.6 \cdot 10^{-6} N=-8.97 \cdot 10^{-5} N$ to the left

3 0

3 years ago

How are the ways in which the pluton and pegmatite minerals form similar?

Rasek [7]

There both minerals and there both

8 0

4 years ago

What is the difference between acceleration and linear acceleration?

Akimi4 [234]

Explanation:

Linear acceleration is a type of acceleration of a body along a straight path or line.

Acceleration is defined as the rate of change of velocity with time.

Acceleration = $\frac{Change in velocity}{time}$

There are different types of acceleration .

linear acceleration is used to describe the rate of change of velocity of a body along a straight path with time.
centripetal acceleration is the rate of change of velocity of a body traveling along a circular path with time. It is directed towards the center.
Angular acceleration is the rate of change of angular velocity.

Learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

6 0

3 years ago

Write a responding to the prompt.<br><br><br><br>What role does mass play in gravitational forces

suter [353]

Gravity is the attraction between two objects that have mass. The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects. Gravity is a force that increases the velocity of falling objects - they accelerate.

5 0

4 years ago