A student conducting the iodine clock experiment accidentally makes an s2o32- stock solution that is too concentrated. how will
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The change which increase the rate of the reaction is by increasing the amount of solution.
<h3>What is the rate of the reaction?</h3>Rate of the reaction gives idea about the speed of the completion of the reaction or the formation of the products.
Given chemical reaction is:
2H₂O₂ 2H₂O + O₂
In the above chemical reaction MnO₂ acts as a catalyst which helps in increasing the rate of the reaction without being involved in the reaction. So the formation of the product depends only on the concentration of the solution. So, by increasing the solution amount will increase in the rate.
Hence, increasing the amount of solution will increase the rate.
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The strategy adopted for for the synthesis of <span>2-bromo-4-nitrobenzoic acid is as follow,
1) First Nitration of Toluene was done because the product formed (4-Nitrotoluene) will direct the next incoming electrophile (i.e. -Br) to ortho position with respect to -CH</span>₃ (ortho para directing) and at meta position with respect to -NO₂ (meta directing).
2) Bromination gave the exact desired product as discussed in point 1.
3) At last oxidation of toluene yield benzoic acid. No other substituent is oxidized other than -CH₃ group.
1) First Nitration of Toluene was done because the product formed (4-Nitrotoluene) will direct the next incoming electrophile (i.e. -Br) to ortho position with respect to -CH</span>₃ (ortho para directing) and at meta position with respect to -NO₂ (meta directing).
2) Bromination gave the exact desired product as discussed in point 1.
3) At last oxidation of toluene yield benzoic acid. No other substituent is oxidized other than -CH₃ group.