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WITCHER [35]
3 years ago
13

A student conducting the iodine clock experiment accidentally makes an s2o32- stock solution that is too concentrated. how will

this affect the rate measurement? reaction 1: 3i- (aq) + s2o82- (aq) -> i3- (aq) + 2so42- (aq) slow reaction 2: i3- (aq) + 2s2o32- (aq) -> 3i- (aq) + s4o62- (aq) fast reaction 3: i3- (aq) + starch (aq) -> 3i- ---- starch (bluish black) fast
Chemistry
1 answer:
cupoosta [38]3 years ago
8 0
Adding (S2O3)2- would affect the reaction mechanism that involves this ion. From the reaction mechanism given above, the equilibrium of step 2 would be affected. Adding the stock solution of (S2O3)2- would shift the equilibrium to the right thus making more products of the said mechanism. Also, the reaction rate of this step would occur faster than the original rate. This is based on Le Chatelier's Prinicple which states that a corresponding change would happen to the equilibrium of a reaction when pressure, concentration of the substances or temperature is changed. So, that after the addition, a color change would appear immediately because I3- would be removed slowly from solution, and would therefore be able to react with starch. 

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Carbons from acetyl CoA are transferred to the citric acid cycle. Which is the first round of the citric acid cycle that could p
Zielflug [23.3K]

Answer:

In the third step of the citric acid cycle, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released.

Explanation:

In the first step of citric acid cycle, acetylCoA combines with a four-carbon molecule, oxaloacetate, forming a six-carbon molecule, citrate.

In the second step, the citrate in the presence of enzyme anicotase is converted into isocitrate.

<u>In the third step, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released leaving behind one five-carbon molecule called as α-ketoglutarate. During this step, NAD⁺ is reduced to form NADH. </u>

<u>This is first round of the citric acid cycle that could possibly release a carbon atom originating from this acetyl CoA.</u>

On series of reaction, another carbon dioxide molecule also being relased and oxaloacetate is regenerated again.

7 0
2 years ago
1. A container holds four times as many moles of CO2 as O2. If the total pressure in the container is 20. atm,
Hitman42 [59]

Answer:

Partial pressure of CO2 = 16 atm

Explanation:

Total number of moles of gases = 4+1 = 5 moles

Mole fraction of CO2 = 4/5

Partial pressure of CO2 = mole fraction of CO2 × total pressure

Partial pressure of CO2 = (4/5) × 20

Partial pressure of CO2 = 16 atm

7 0
2 years ago
The sodium-potassium pump is called an electrogenic pump because it
kvv77 [185]

Answer:

Contributes to the membrane potential.

Explanation:

Sodium-potassium pump: In cellular physiology, a protein which is identified in many cells that helping in to maintain the higher concentration of potassium ions inside than that is in the surrounding medium and maintain the lower concentration of sodium ions inside than that of the surrounding medium.

This unbalanced charge transfer contributes in the separation of charge across the cell membrane. Sodium-potassium pump is known for important contributor to action potential which is produce by nerve cells.

8 0
3 years ago
Create a model of the atoms of a substance moving through the solid, liquid, and gas states.
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5 0
2 years ago
Read 2 more answers
How many atoms are in 2.10 g of K? molar mass of K=39.10g/mole.
Alborosie

Answer:

<h3>The answer is option B</h3>

Explanation:

To calculate the number of atoms we must first calculate the number of moles

Molar mass = mass / number of moles

number of moles = mass / Molar mass

Molar mass (K) = 39.10mole

mass = 2.10g

number of moles = 2.10/ 39.10

= 0.0537mol

After that we use the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10^23 entities

Number of K atoms is

N = 0.0537 × 6.02 × 10^13

<h3>N = 3.23×10^22 atoms of K</h3>

Hope this helps you.

5 0
3 years ago
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