The answer is D you correct
Answer:
7.51 × 10¹⁷
Explanation:
1. Calculate the <em>energy of one photon</em>
The formula for the energy of a photon is
E = hc/λ
h = 6.626 × 10⁻³⁴ J·s; c = 2.998 × 10⁸ m·s⁻¹
λ = 531 nm = 531 × 10⁻⁹ m Insert the values
E = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(531 × 10⁻⁹)
E = 3.741× 10⁻¹⁹ J
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2. Calculate the number of photons
Divide the total energy by the energy of one photon.
No. of photons = 0.281 × 1/3.741 × 10⁻¹⁹
No. of photons = 7.51 × 10¹⁷ photons
Answer:
CN⁻(aq) + H⁺(aq) ⇒ HCN(aq)
Explanation:
Let's consider the following molecular equation.
NaCN(aq) + HI(aq) ⇒ NaI(aq) + HCN(aq)
HI is a strong electrolyte so it exists mostly in the ionic form. HCN is a weak electrolyte so it exists mostly in the molecular form.
The full ionic equation includes all the ions and the molecular species.
Na⁺(aq) + CN⁻(aq) + H⁺(aq) + I⁻(aq) ⇒ Na⁺(aq) + I⁻(aq) + HCN(aq)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
CN⁻(aq) + H⁺(aq) ⇒ HCN(aq)
Answer:
electronic configuration: 1s^2,2s^2,2p^3
name: nitrogen
unpaired electron: 3
Explanation: