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Anna007 [38]
3 years ago
14

Use the drop-down menus to complete the sentences.

Physics
2 answers:
mars1129 [50]3 years ago
7 0

Answer:

1) thinner, diverge

2) thicker, converge

Explanation:

i got it right thanks to the other user :)

Grace [21]3 years ago
5 0

Answer:

1) thinner, diverge

2) thicker, converge

Explanation:

i got it right

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Does wind have atoms and molecules in it?
Likurg_2 [28]
<span>
Of course.  Wind is air in motion, and the gases in air are composed of
all the usual familiar stuff ... atoms, molecules, mass, etc.  That's how
the wind moves things ... it has momentum and kinetic energy, which
get transferred to the things that move in the wind.</span>


4 0
4 years ago
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What is the difference between a 4x100 and a 4x400 relay
qaws [65]
A 4x100 relay is where 4 people run 100 meters and a 4x400 relay is where 4 people run 400 meters
6 0
3 years ago
How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?
DiKsa [7]
<span>Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
(1) => F = 68 * 1.2
F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)</span>
4 0
3 years ago
Read 2 more answers
A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800
Arada [10]

Explanation:

The given data is as follows.

            m = 5000 kg,            h = 800 km = 0.8 \times 10^{6} m

    R_{e} = 6.37 \times 10^{6} m,    r = R + h = 7.17 \times 10^{6} m

   M_{e} = 5.98 \times 10^{24} kg,   G = 6.67 \times 10^{-11} Nm^{2}/kg^{2}

As we know that,

              \frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}

                      v = \sqrt{\frac{GM_{e}}{r^{2}}}

And, it is known that formula to calculate angular velocity is as follows.

               \omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}

                            v = \sqrt{\frac{GM_{e}}{r^{3}}}

                               = \sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}

                                = 1.0402 \times 10^{-3} rad/s

Thus, we can conclude that speed of the satellite is 1.0402 \times 10^{-3} rad/s.

6 0
3 years ago
Pourquoi doit on toujours préciser le référentiel dans le quel est étudié le mouvement d'un système?
Vedmedyk [2.9K]

Answer:

The movement of an object depends on the reference frame, so it is important to predicate it.

Explanation:

4 0
2 years ago
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