The equation that scientists could use to find the wavelength of the emission lines of the hydrogen atom would be that of Balmer.
The wavelength of the emission lines of the hydrogen atom can be derived using the Balmer series:
1/λ 
Where λ = wavelength, 
= Rydberg constant, and n = level of the original orbital.
The equation becomes applicable in getting the wavelength of emitted light when electrons in hydrogen atoms transition from higher (n) orbital to lower orbital (2) levels.
More on the Balmer series can be found here: brainly.com/question/5295294
Answer:
The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ
Explanation:
From Arrhenius equation showing the temperature dependence of reaction rates.
where
k = rate constant
A = Frequency or pre-exponential factor
Ea = energy of activation
R = The universal gas constant
T = Kelvin absolute temperature
we have
Where
f = fraction of collision with energy higher than the activation energy
Ea = activation energy = 10.0kJ = 10000J
R = universal gas constant = 8.31 J/mol.K
T = Absolute temperature in Kelvin = 400K
In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature
Plugging in the values into the equation relating f to activation energy we get
or f = 
= 20.22 moles of argon have an energy of 10.0 kJ or greater
D I believe peace out Hope this helps
I am not sure about my answer, but I think that it's density allows it to fall to the ground/floor.
Answer:Please refer the attachment for the structure. The name of the compound is 4-chloro butan-2-one
Explanation:
When we treat CH₂=CHCOCH₃ with one equivalent of HCl , the alkene reacts with HCl to undergo electrophilic addition to the C=C pi bond . The reaction is similar to Markowinkoffs addition reaction. The reaction leads to the formation of Cl-CH₂-CH₂-COCH₃ .
Kindly refer the attachment for mechanism of the reaction.
We can ascertain the structure of A from the NMR data available :
The NMR spectra has a absorption signal at 2.2 which can be ascertained to the CH₃(referred as 3 in structure protons) group attached next to the the carbonyl group as these protons generally appear at around 2.0-2.5ppm. These protons are slightly downfield as they are attached next to sp² hybridized carbonyl carbon. The spin multiplicity shown by these protons is singlet which also shows that no coupling occurs as there are no available protons at the neighboring carbonyl carbon.
The NMR spectra has a absorption signal at 3.05 and it can be ascertained to CH₂ group next to carbonyl group (referred as 2 in the structure). The protons appear slightly downfield due to carbonyl group and weak electron withdrawing inductive effect of chlorine atom. The spin multiplicity of these protons is triplet on account of coupling with the neighboring CH₂ protons next to Cl.
The NMR spectra has a absorption signal at 3.79 and it can be ascertained to CH₂ group next to chlorine group (referred as 1 in the structure). The protons appear slightly more downfield due to strong electron withdrawing inductive effect of Cl atom. The spin multiplicity of these protons is triplet on account of coupling with the neighboring CH₂ protons next to carbonyl group.
Kindly refer attachment for reaction mechanism and structure.
