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gavmur [86]
3 years ago
5

Isotopes of the same element have the same number of ________ and a different number of _____.

Chemistry
2 answers:
vovangra [49]3 years ago
5 0
<span>C.) Protons, neutrons. Hope it helps :)</span>
Alona [7]3 years ago
5 0
C.) Protons and neutrons. Isotopes have same atomic number but different atomic mass number.
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The equation of which of the below scientists could be used to find the wavelength of the emission lines of the hydrogen atom:
mihalych1998 [28]

The equation that scientists could use to find the wavelength of the emission lines of the hydrogen atom would be that of Balmer.

The wavelength of the emission lines of the hydrogen atom can be derived using the Balmer series:

        1/λ  = R_H (1/4 - 1/n^2)

Where λ = wavelength, R_H = Rydberg constant, and n = level of the original orbital.

The equation becomes applicable in getting the wavelength of emitted light when electrons in hydrogen atoms transition from higher (n) orbital to lower orbital (2)  levels.

More on the Balmer series can be found here: brainly.com/question/5295294

3 0
2 years ago
Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 10.0 kJ or greater.
nikdorinn [45]

Answer:

The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ

Explanation:

From Arrhenius equation showing the temperature dependence of reaction rates.

K = Ae^{\frac{Ea}{RT} } where

k = rate constant

A = Frequency or pre-exponential factor

Ea   =       energy of activation

R = The universal gas constant

T = Kelvin absolute temperature

we have

f = e^{\frac{Ea}{RT} }

Where

f = fraction of collision with energy higher than the activation energy

Ea = activation energy = 10.0kJ = 10000J

R = universal gas constant = 8.31 J/mol.K

T = Absolute temperature in Kelvin = 400K

In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature  

Plugging in the values into the equation relating f to activation energy we get

f = e^{\frac{10000J}{(8.31J/((mol)(K)))(400K)} } or f = e^{3.01} = 20.22 moles of argon have an energy of 10.0 kJ or greater

5 0
3 years ago
NEED HELP ASAP PLEASE!!! EMERGENCY!
N76 [4]
D I believe peace out Hope this helps
4 0
3 years ago
Read 2 more answers
What property of air allows it to flow down to the floor?​
Mandarinka [93]

I am not sure about my answer, but I think that it's density allows it to fall to the ground/floor.

5 0
3 years ago
Identify product A from the given 1H NMR data. Treatment of CH2═CHCOCH3 with one equivalent of HCl forms compound A. A exhibits
Blizzard [7]

Answer:Please refer the attachment for the structure. The name of the compound is 4-chloro butan-2-one

Explanation:

When we treat CH₂=CHCOCH₃ with one equivalent of HCl , the alkene reacts with HCl to undergo  electrophilic addition to the C=C pi bond . The reaction is similar to Markowinkoffs addition reaction. The reaction leads to the formation of Cl-CH₂-CH₂-COCH₃ .

Kindly refer the attachment for mechanism of the reaction.

We can ascertain the structure of A from the NMR data available :

The NMR spectra has a absorption signal at 2.2 which can be ascertained to the CH₃(referred as 3 in structure protons)  group attached next to the  the carbonyl group as these protons generally appear at around 2.0-2.5ppm. These protons are slightly downfield as they are attached next to sp² hybridized carbonyl carbon. The spin multiplicity shown  by these protons is singlet which also shows that no coupling occurs as there are no available protons at  the neighboring carbonyl carbon.  

The NMR spectra has a absorption signal at 3.05  and it can  be ascertained  to CH₂ group  next to carbonyl group (referred as 2 in the structure). The protons appear slightly downfield due to carbonyl group and weak electron withdrawing inductive  effect of chlorine atom. The spin multiplicity of these protons is triplet on account of coupling with the neighboring CH₂ protons next to Cl.

The NMR spectra has a absorption signal at 3.79  and it can  be ascertained  to CH₂ group  next to chlorine group (referred as 1 in the structure). The protons appear slightly more  downfield due to strong electron withdrawing inductive effect of Cl atom. The spin multiplicity of these protons is triplet on account of coupling with the neighboring CH₂ protons next to carbonyl group.

Kindly refer attachment for reaction mechanism and structure.

6 0
3 years ago
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