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julia-pushkina [17]
3 years ago
7

How are elements and compounds different?

Chemistry
2 answers:
Nataliya [291]3 years ago
3 0

Answer:

Elements only contain one type of atoms while compounds contain two or more types of atoms.

Explanation:

An example of an element is sodium --> Na (only Na atoms)

An example of a compound can be water --> H2O (contain H and O atoms)

*But the particles within a compound are all the same.

krok68 [10]3 years ago
3 0
No. Elements are pure substances which are composed of only one type of atom. Compound are substances which are formed by two or more different types of elements that are united chemically in fixed proportions.
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Can someone help me with these three Chemistry questions?
Xelga [282]
There are 6 molecules of Mg3(PO4)2
6 × 3 = 18 Mg
6 × 4 × 2 = 48 O

8 0
3 years ago
At constant pressure, how are the temperature and volume of a gas related?
RideAnS [48]

Answer:

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

4 0
2 years ago
A solution has a [OH−] of 1 x 10−12. What is the pOH of this solution?<br> 2<br> 7<br> 10<br> 12
strojnjashka [21]
-log (1×10^-12) is how you calculate the pOH which in this case is 12
7 0
3 years ago
Read 2 more answers
Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -&gt; 2Fe(s) + 3CO(g)
Gelneren [198K]

Answer:

ΔS = +541.3Jmol⁻¹K⁻¹

Explanation:

Given parameters:

Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹

Standard Entropy of C = 5.7Jmol⁻¹K⁻¹

Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹

Standard Entropy of CO = 198Jmol⁻¹K⁻¹

To find the entropy change of the reaction, we first write a balanced reaction equation:

                              Fe₂O₃ +  3C →  2Fe + 3CO

To calculate the entropy change of the reaction we simply use the equation below:

      ΔS = ∑S_{products} - ∑S_{reactants}

Therefore:

     ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1

                          ΔS = +541.3Jmol⁻¹K⁻¹

5 0
3 years ago
A mass of 2kg has a kinetic energy of 16J.what is the momentum of the body?​
juin [17]

Explanation:

mass -2kg

energy -16j

2

k.e -1/2mv

2

16j= 1/2×2×V

2

16× 2/2 =V

2

16 = V

√16= V

V= 4m/s

Then

momentum=MV

=2×4

=8kgm/s

3 0
3 years ago
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