When The rate of effusion is inversely proportional to the √molar mass of the substance.
and we have R(He) = 1L / 4.5 min so,
R(He)/R(Cl2) = (molar mass of Cl2/ molar mass of He)^0.5
and when we have the molar mass of Cl2 = 70.9 & the molar mass of He = 4
so by substitution:
(1L/4.5 min)/ R(Cl2) = (70.9 / 4)^0.5
(1L/4.5 min) / R(Cl2) = 4.21
∴R(Cl2) = (1L/4.5 min) / 4.21 = 1L/ (4.5*4.21)min = 1 L / 18.945 min
∴Cl2 will take 18.945 min for 1 L to effuse under identical conditions
Usual s I have no idea sorry
The empirical formula : Fe₂O₃
<h3>Further explanation</h3>
Given
34.97g of Iron
15.03g of Oxygen
Required
The empirical formula
Solution
Mol ratio :
Fe(Iron) : 34.97 g : 56 g/mol = 0.624
O(Oxygen) : 15.03 g : 16 g/mol = 0.939
Divide by 0.624 :
Fe : O = 1 : 1.5
Fe : O = 2 : 3
Answer:
it's because aluminium is a ductile material