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Nataly [62]
3 years ago
10

Suppose there are two known compounds containing the generic elements X and Y. You have a 1.00-g sample of each compound. One sa

mple contains 0.25 g of X and the other contains 0.33 g of X. Identify plausible sets of formulas for these two compounds. Check all that apply.
Chemistry
1 answer:
Lapatulllka [165]3 years ago
8 0

I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y, for the following reason: 

If you look at the combining masses of X and Y in each of the two compounds, 

The first compound contains 0.25g of X combined with 0.75g of Y 
so the ratio (by mass) of X to Y = 1 : 3 

The second compound contains 0.33 g of X combined with 0.67 g of Y 
so the ratio (by mass) of X to Y = 1 : 2 

Now, you suppose to prepare each of these two compounds, starting with the same fixed mass of element Y ( I will choose 12g of Y for an easy calculation!) 

The first compound will then contain 4g of X and 12g of Y 
The second compound will then contain 6g of X and 12g of Y 

<span>The ratio which combined the masses of X and the fixed mass (12g) of Y
= 4 : 6 
<span>or 2 : 3 </span>

So, the ratio of MOLES of X which combined with the fixed amount of Y in the two compounds is also = 2 : 3 </span>

The two compounds given with the plausible formula must therefore contain the same ratio.

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4.50 g of Nacl react with 10.00 g of Agno3 to produce 7.93 g of Agcl.if the theroretical amount of agcl that can be formed is 8.
Allushta [10]
Answer: 94.07%
Explanation:
Percentage yield can be calculated by the formula
%yield = Experimental yield/Theoretical yield x100
Experimental yield = 7.93g
Theoretical yield = 8.43
%yield = Experimental yield/Theoretical yield x100
%yield = 7.93/8.43 x 100 = 94.07%
6 0
3 years ago
Calculate the amount of heat water absorbs from a piece of hot metal using the following data: 75.0 g of cold water is placed in
AysviL [449]

Answer:

Amount of heat absorbed by water is 2604.54 J.

Explanation:

Amount of heat absorbed by water = m_{water}\times C_{water}\times \Delta T_{water}

where m represents mass, C represents specific heat and \Delta T represents change in temperature.

Here m_{water}=75.0 g , C_{water}=4.184J/(g.^{0}\textrm{C}) and \Delta T = (final temperature - initial temperature) = (29.5-21.2) ^{0}\textrm{C} = 8.3 ^{0}\textrm{C}

So, amount of heat heat absorbed by water

     = (75.0g)\times (4.184\frac{J}{g.^{0}\textrm{C}})\times (8.3^{0}\textrm{C})

     = 2604.54 J

8 0
4 years ago
What must differ beween the atom of two different elements?​
kodGreya [7K]
The number of protons must differ between two different elements
5 0
4 years ago
Read 2 more answers
As a bond between a hydrogen atom and a sulfur atom is formed, electrons are(1) shared to form an ionic bond(2) shared to form a
Alina [70]
Let's define an ionic and covalent bond.
An ionic bond occurs between a metal and non-metal. These electrons are transferred between atoms. A Covalent bond occurs between a nonmetal and a nonmetal. These electrons are shared between atoms.
First, identify whether each element is metal or nonmetal. If you need a little help, refer to an online periodic table for guidance.
We see that both Hydrogen and Sulfur are nonmetals. That eliminates both choice 1 and 3.
Then, understanding that within covalent bonds, electrons are shared, choice 4 is eliminated.
Thus, the answer is 2.
8 0
3 years ago
Please respond guys I’ll give brainliest and 100 points
Contact [7]

Answer:

Name

Atomic Number

Atomic Symbol

Atomic Weight

Phase

Color

Classification

Group in Periodic Table

Group Name

Period in Periodic Table

Block in Periodic Table

Electronic Configuration

Melting Point

Boiling Point

Electronic Shell Structure

CAS Number

Neighborhood Elements

Lithium

3

Li

6.941

Solid

Silver

alkali metal

1

lithium family  

2

s

[He] 2s1

180.54 °C

1342 °C

2, 1

CAS7439-93-2

Neighborhood Elements of Lithium

Cesium

55

Cs

132.90545

Solid

Silver

alkali metal

1

lithium family  

6

s

[Xe] 6s1

28.44 °C

671 °C

2, 8, 18, 18, 8, 1

CAS7440-46-2

Neighborhood Elements of Cesium

Explanation:

4 0
3 years ago
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