Answer:
The molar concentration of 
ions in the given amount of sample is 
Explanation:
Given that,
Mass of sample = 21.5 g
0.07 % (m/m) of copper (II) sulfate in plant fertilizer
This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present
So, in 20 g of plant fertilizer
,
of copper (II) sulfate is present.
To calculate the molarity of solution, we use the equation:
Mass of solute (copper (II) sulfate) = 0.0151 g
Molar mass of copper (II) sulfate = 159.6 g/mol
Volume of solution = 2.0 L
The chemical equation for the ionization of copper (II) sulfate follows:
1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions
Molarity of copper (II) ions =
Hence, the molar concentration of ions in the given amount of sample is
Answer:
organic molecules made up of carbon and hydrogen elements joined together in long groups called hydrocarbons. The arrangement of these hydrocarbon chains, and their interaction with each other, determines fat type.
Answer:
In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as
c=4.18Jg∘C
Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.
Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.
In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.
What if you wanted to increase the temperature of 1 g of water by 2∘C ?
This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.
And there you have it. The equation that describes all this will thus be
q=m⋅c⋅ΔT , where
q - heat absorbed
m - the mass of the sample
c - the specific heat of the substance
ΔT - the change in temperature, defined as final temperature minus initial temperature
In your case, you will have
q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C
q=10,450 J
Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
<em />
An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
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Thus,<em> the three statements are true</em>.
Answer:
d. it has a high boiling point
Explanation:
all ionic compounds with ionic bonds have high boiling points
