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3 years ago

10. Which one of the following statements about sulfuric acid is correct? A. Sulfuric acid has little effect on metals.

Chemistry

1 answer:

Orlov [11]3 years ago

7 0

C. Sulfuric acid is a strong oxidizing agent.

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Why do we use 51.0mL of NaOH but only 50.0mL of HCl?

bixtya [17]

Answer

Na OH reacts with H Cl and forms Na Cl and H₂O

NaOH + HCl → NaCl + H₂O

Here we can see that 1 mole of NaOH reacting with 1 mole of HCl and forming 1 mole of NaCl and 1 mole of H₂O

when NaOH and HCl are added together in equal amount then they will completely neutralize each other but NaOH is hygroscopic in nature which means it can absorb water from air so it will not be weighted accurately.

hence, for neutralization we will take extra NaOH.

3 0

2 years ago

Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

harkovskaia [24]

Answer:

The frequency of this light is $6.98\times 10^{14} s^{-1}$ .

Explanation:

Wavelength of the light = $\lambda = 430 nm=4.30\times 10^{-7} m$

Speed of the light = c = $= 3\times 10^8 m/s$

Frequency of the light = $\nu$

$\nu =\frac{c}{\lambda }$

$\nu =\frac{3\times 10^8 m/s}{4.30\times 10^{-7} m}=6.98\times 10^{14} s^{-1}$

The frequency of this light is $6.98\times 10^{14} s^{-1}$ .

5 0

3 years ago

What are the SI units of frequency?

Tomtit [17]

SI unit of frequency is Hertz(Hz)

7 0

2 years ago

At 80 ∘C, Kc=1.87×10^−3 for the reaction PH3BCl3(s)⇌PH3(g)+BCl3(g)

daser333 [38]

Answer:

A) he equilibrium concentration of PH3 = 0.0432M

B) he equilibrium concentration of BCl3 = 0.0432M

C) what is the minimum mass of PH3BCl3(s) that must be added to the flask to achieve equilibrium = 1.69g

Explanation:

The detailed steps and appropriate calculation is as shown in the attached file.

6 0

3 years ago

you are given a solution of lead nitrate. use any of the solution used in this experiment to form a white precipitate of lead ch

Vesnalui [34]

We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.

If a chlorine solution is used we will have the following reaction:

$Pb(NO_{3)2}+2Cl^-\rightarrow PbCl_2+2NO^-_3$

So, with a chlorine solution, we will have a white precipitate of lead chloride.

7 0

7 months ago