Pure Substances cannot be separated easily or, sometimes at all.
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Answer:
1.42 M
Explanation:
First calculate the amount of moles.
that's done by dividing the mass with the molecular mass so 660g / 310.18 g/mol = 2.13 mol
Then you can calculate the molarity by dividing the moles with the volume so 2.13 mol / 1.5 l = 1.42 M
(without rounding: 1.418531175 M)
Answer: the density of the solid metal is 22.5176 g/cm
Explanation:
Given that;
mass of solid metal = 255 g
the cylinder and its contents weigh 101g less than before
also given that density of mercury = 13.6 g/cm³
Volume of the solid metal = volume of mercury which was absent in the first weighing
so let volume = Vcm³
Mass of mercury which was absent in the first weighing = density × volume
= 13.6 g/cm³ × Vcm³ = 13.6V g
now since the cylinder and its contents weigh 101g less than before,
it means the difference in mass between the solid and metal and the mass of mercury is equal to 101 g
so
255 - 13.6V g = 101g
13.6V g = 255 g - 101 g
13.6V = 154
V = 154 / 13.6
V = 11.3245 cm³
Now Density of solid metal will be;
⇒ mass / volume
= 255 / 11.3245
= 22.5176 g/cm
Therefore, the density of the solid metal is 22.5176 g/cm
To calculate the concentration of the base based on the titration, the concept used is the equal of number of equivalence of the acid used to that of the base. From this,
Na x Va = Nb x Vb
For HBr and KOH, molarity is equal to normality. Substituting the known values,
(0.75 M) x (22.6 mL - 0 mL) = Nb x (37.5 mL - 0.5 mL)
Nb = 0.46 N
Mb = 0.46 M
Thus, the concentration of the base is approximately 0.46 M.
