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Sindrei [870]
3 years ago
8

49 points~!

Chemistry
2 answers:
Arisa [49]3 years ago
6 0

1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol

a. this reaction is exothermic as ΔH is -ve

b. the equilibrium will shift 2 the left if nitrogen gas is removed

c. the equilibrium shift 2 the right if the temperature is lowered

d. the equilibrium shift 2 the left if ammonia (NH3) is added

e. principle of thermodynamic potential or Gibbs energy is used to answer B-D

Kitty [74]3 years ago
6 0

e. I will answer the last one first - the equation describes a reversible reaction and the equilibrium is determined by the Le Châtelier's principle.

a. It is exothermic.

b. It will shift towards the reactants side (N2+H2).

c. It will shift towards the product side (NH3).

d.  It will shift towards the reactants side (N2+H2).

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The gas left in a used aerosol can is at a pressure of 103 kPa at 25.0 °C. If the can heats up to 50.0 °C, what is the pressure
Anton [14]
The question mentions a change in temperature from 25 to 50 °C. With that, the aim of the question is to determine the change in volume based on that change in temperature. Therefore this question is based on Gay- Lussac's Gas Law which notes that an increase in temperature, causes an increase in pressure since the two are directly proportional (once volume remains constant). Thus Gay-Lussac's Equation can be used to solve for the answer.
Boyle's Equation:     \frac{P_{1} }{T_{1} }    =   \frac{P_{2} }{T_{2} }
Since the initial temperature (T₁) is 25 C, the final temperature is 50 C (T₂) and the initial pressure (P₁) is 103 kPa, then we can substitute these into the equation to find the final pressure (P₂).
                      \frac{P_{1} }{T_{1} }    =   \frac{P_{2} }{T_{2} }∴ by substituting the known values,                 ⇒       (103 kPa) ÷ (25 °C)  =  (P₂) ÷ (50 °C)
                 ⇒                                  P₂  =  (4.12 kPa · °C) (50 °C)
                                                            =  206 kPa 
Thus the pressure of the gas since the temperature was raised from 25 °C to 50 °C is 206 kPa

3 0
3 years ago
Two solutions are created by mixing one solution containing lithium nitrate with one containing sodium phosphate.
babunello [35]

Answer:

Solution A that will form a precipitate with Ksp = 2.3 x 10−4

Explanation:

                                  Li₃PO₄ ⇄ 3 Li⁺(aq) + PO₄³⁻(aq)

                                                     3S               S

Where S = Solubility(mole/lit) and Ksp = Solubility product

⇒ Ksp = (3S)³ x (S)

⇒ 27S⁴ = 2.3x10−4

⇒ S = 0.05 mol/lit

Concentration of Li₃PO₄ precipitate = 0.05

<u>Solution A </u>

0.500 lit of a 0.3 molar LiNO₃ contains 0.5 x 0.3 = 0.15 mole

0.4 lit of a 0.2 molar Na₃PO₄ contains = 3 x 0.4 x 0.2 = 0.24 mole

                                     3 LiNO₃ + Na₃PO₄ → 3 NaNO₃ + Li₃PO₄

(Mole/Stoichiometry)    \frac{0.15}{3}                \frac{0.24}{1}

                                   = 0.05            = 0.24

Since from (Mole/Stoichiometry) ratio we can conclude that LiNO₃ is limiting reagent.

So concentration of Li₃PO₄ is equal to 0.05.

                       

6 0
2 years ago
Who was the first U.S. secretary of state to ever visit the remote cook islands in the south pacific
pogonyaev

Answer:

I think it was Hillary Clinton.

Explanation:

6 0
3 years ago
Why are basic radicals classified into six groups?​
Alona [7]

Basic radicals (cations) have been divided into groups based on Ksp values

4 0
2 years ago
Que significa arte m m k,
Svetradugi [14.3K]

Answer:

Explanation:

huh

7 0
3 years ago
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