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Sindrei [870]
3 years ago
8

49 points~!

Chemistry
2 answers:
Arisa [49]3 years ago
6 0

1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol

a. this reaction is exothermic as ΔH is -ve

b. the equilibrium will shift 2 the left if nitrogen gas is removed

c. the equilibrium shift 2 the right if the temperature is lowered

d. the equilibrium shift 2 the left if ammonia (NH3) is added

e. principle of thermodynamic potential or Gibbs energy is used to answer B-D

Kitty [74]3 years ago
6 0

e. I will answer the last one first - the equation describes a reversible reaction and the equilibrium is determined by the Le Châtelier's principle.

a. It is exothermic.

b. It will shift towards the reactants side (N2+H2).

c. It will shift towards the product side (NH3).

d.  It will shift towards the reactants side (N2+H2).

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One part nitrogen gas combines with one part oxygen gas to form how many part(s) dinitrogen monoxide (nitric oxide)?
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Answer : The one part nitrogen gas combines with one part oxygen gas to form one part of dinitrogen monoxide.

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

When nitrogen gas combines with oxygen gas then it react to give dinitrogen monoxide or nitrous oxide.

The balance chemical reaction will be:

2N_2(g)+O_2(g)\rightarrow 2N_2O(g)

By the stoichiometry we can say that, 2 parts of nitrogen gas combines with 1 part of oxygen gas to give 2 parts of dinitrogen monoxide or nitrous oxide.

First we have to determine the limiting reagent.

From the reaction we conclude that,

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Now we have to determine the moles of dinitrogen monoxide.

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So, 1 mole of nitrogen gas combine to give 1 mole of dinitrogen monoxide

Thus, the one part nitrogen gas combines with one part oxygen gas to form one part of dinitrogen monoxide.

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When a sample of a compound in the vitamin D family was burned in a combustion analysis, 5.983 mg of the compound gave 18.490 mg
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<span>divide each by the smallest value, giving you the chemical formula as:
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C27H44O</span>
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