Question

The x component of a velocity vector that has an angle of 37° (to the +x) has a magnitude of 4.8 m/s. What is the magnitude of the velocity? What is the y component of the velocity?

Answer 1

Answer:

Magnitude of velocity V = 6.015 m/sec

Y component of velocity = 3.61 m/sec

Explanation:

We have given magnitude of velocity in x direction, that is horizontal component $V_X=3.8m/sec$

Angle with x axis = 37°

We know that horizontal component $V_X=Vcos\Theta$

So $4.8=Vcos37^{\circ}$

$V=6.015m/sec$

Y component of velocity is given by $V_Y=Vsin\Theta =6.015sin37^{\circ}=3.61m/sec$