A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?
2 answers:
Answer:
The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.
Explanation:
Given that,
Force = 1500 N
Area
We need to find the force to be applied on a 0.8 m2 piston to lift the crate
Using formula of pressure
The pressure is the force upon area.
Where, F = force
A = area
Pressure for first force,
...(I)
Pressure for second force,
...(II)
Equate the equations (I) and (II)
Hence, The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.
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Answer:
Explanation:
a ) Time period T = 2 s
Angular velocity ω = 2π / T
= 2π / 2 = 3.14 rad /s
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=356.25
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I₂ = 200 + 25 X 1.5 X 1.5
= 256.25
b ) We apply law of conservation of momentum
I₁ X ω₁ = I₂ X ω₂
ω₂ = I₁ X ω₁ / I₂
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ω₂ = 4.365 rad s⁻¹
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=1/2 I₂ X ω₂² - 1/2 I₁ X ω₁²
.5 X 256.25 X 4.365² - .5 X 356.25 X 3.14²
= 684.95 J
This energy comes from work done against the centripetal pseudo -force.