All categories

3 years ago

A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?

Physics

2 answers:

Aleks04 [339]3 years ago

7 0

25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
1200/25 is equal to 48 N

ki77a [65]3 years ago

7 0

Answer:

The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.

Explanation:

Given that,

Force = 1500 N

Area $A= 25 m^2$

We need to find the force to be applied on a 0.8 m2 piston to lift the crate

Using formula of pressure

The pressure is the force upon area.

$P =\dfrac{F}{A}$

Where, F = force

A = area

Pressure for first force,

$P =\dfrac{F}{A}$

$P =\dfrac{1500}{25}$ ...(I)

Pressure for second force,

$P =\dfrac{F}{0.8}$ ...(II)

Equate the equations (I) and (II)

$\dfrac{1500}{25}=\dfrac{F}{0.8}$

$F=\dfrac{1500\times0.8}{25}$

$F=48\ N$

Hence, The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.

You might be interested in

Compare and contrast the way molecules behave in liquid to the way they behave in solids and gases.

Vitek1552 [10]

In liquids, molecules particles are close together but move in random directions.

In solids, they are closely packed together and they vibrate a little.

In gases, they love around really quickly and are farther apart (even more than liquids).

3 0

3 years ago

Read 2 more answers

A force of 12 N changes the momentum of a toy car from 3kgm/s t0 10kgm/s. Calculate the time the force took to produce this chan

yan [13]

Answer:

Time = 0.58 seconds

Explanation:

Given the following data;

Initial momentum = 3 kgm/s

Final momentum = 10 kgm/s

Force = 12 N

To find the time required for the change in momentum;

First of all, we would determine the change in momentum.

$Change \; in \; momentum = final \; momentum - initial \; momentum$

$Change \; in \; momentum = 10 - 3$

Change in momentum = 7 kgm/s

Now, we can find the time required;

Note: the impulse of an object is equal to the change in momentum experienced by the object.

Mathematically, impulse (change in momentum) is given by the formula;

$Impulse = force * time$

Making "time" the subject of formula, we have;

$Time = \frac {impulse}{force}$

Substituting into the formula, we have;

$Time = \frac {7}{12}$

Time = 0.58 seconds

6 0

3 years ago

What happens when you brake earphones in to smaller and smaller pieces

nikklg [1K]

They dont work because you crushed them duh

5 0

3 years ago

A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2 m v₀²

v = √2 v₀

6 0

3 years ago

Dos cargas iguales de 10^-7C estan separadas por una distancia de 2m. calcule la fuerza con que se repelen

m_a_m_a [10]

Answer:

$F=2.25\times 10^{-5}\ N$

Explanation:

According to question,

Charge 1 and charge 2 are $10^{-7}\ C$

The distance between charges is 2 m

We need to find the force with which two positive charges repel. It is called electrostatic force of repulsion. It can be given by :

$F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (10^{-7})^2}{2^2}\\\\F=2.25\times 10^{-5}\ N$

So, the electric force of repulsion is $2.25\times 10^{-5}\ N$ .

8 0

3 years ago