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4 years ago

A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?

Physics

2 answers:

Aleks04 [339]4 years ago

7 0

25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
1200/25 is equal to 48 N

ki77a [65]4 years ago

7 0

Answer:

The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.

Explanation:

Given that,

Force = 1500 N

Area $A= 25 m^2$

We need to find the force to be applied on a 0.8 m2 piston to lift the crate

Using formula of pressure

The pressure is the force upon area.

$P =\dfrac{F}{A}$

Where, F = force

A = area

Pressure for first force,

$P =\dfrac{F}{A}$

$P =\dfrac{1500}{25}$ ...(I)

Pressure for second force,

$P =\dfrac{F}{0.8}$ ...(II)

Equate the equations (I) and (II)

$\dfrac{1500}{25}=\dfrac{F}{0.8}$

$F=\dfrac{1500\times0.8}{25}$

$F=48\ N$

Hence, The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.

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3 years ago

Suppose a child drives a bumper car head on into the side rail, which exerts a force of 3900 N on the car for 0.55 s. Use the in

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Answer:

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Explanation:

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Impulse is the product of force and the time elapsed on impact

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v1 is the initial velocity of the car

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The final momentum = mv2

where v2 is the final momentum of the car.

The problem translates into the equation below

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