Answer:
The associated SI unit of force and weight is the Newton, with 1 kilogram weighing 9.8 Newtons under standard conditions on the Earth's surface. However, in the US common units, the pound is the unit of force (and therefore weight). The pound is the widely used unit for commerce.
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Frequency is the vibration of noise and the vibration determines the pitch, which we depend on to be a pitch or frequency we can hear. If it's too high or too low our ears can't hear it
Answer:
a) if we assume that the water does not spill, Beaker B weighs more than beaker S, or which in this case Beaker A weighs more
b) If it is spilled in water the weight of the two beakers is the same
Explanation:
The beaker weight is
beaker A
W_total = W_ empty + W_water
Beaker B
W_total = W_ empty + W_water + W_roca
a) if we assume that the water does not spill, Beaker B weighs more than beaker S, or which in this case Beaker A weighs more
b) If it is spilled in water, the weight of the two beakers is the same because the amount of liquid spilled and equal to the weight of the stone, therefore the two beakers weigh the same
Explanation:
The given data is as follows.
k = 130 N/m,
= 17 cm = 0.17 m (as 1 m = 100 cm)
mass (m) = 2.8 kg
When the spring is compressed then energy stored in it is as follows.
Energy = ![\frac{1}{2}kx^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dkx%5E%7B2%7D)
Now, spring energy gets converted into kinetic energy when the box is launched.
So,
= ![\frac{1}{2}mv^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D)
= ![\frac{1}{2} \times 2.8 \times v^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%202.8%20%5Ctimes%20v%5E%7B2%7D)
![v^{2} = \frac{3.757}{2.8}](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20%5Cfrac%7B3.757%7D%7B2.8%7D)
= 1.34
v = 1.15 m/sec
Now,
Frictional force = ![\mu \times mg](https://tex.z-dn.net/?f=%5Cmu%20%5Ctimes%20mg)
= ![0.15 \times 2.8 \times 9.8](https://tex.z-dn.net/?f=0.15%20%5Ctimes%202.8%20%5Ctimes%209.8)
= 4.116 N
Also, Kinetic energy = work done by friction
1.8515 =
d = 0.449 m
Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.