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3 years ago

if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.

Physics

1 answer:

Likurg_2 [28]3 years ago

6 0

Answer:

4 seconds

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -5 m/s²

Find: t

v = at + v₀

0 m/s = (-5 m/s²) t + 20 m/s

t = 4 s

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3 years ago

"When Baby Ian is held horizontally on his back, he sometimes makes an embracing motion by arching his back, extending his legs,

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Answer:

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Explanation:

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3 years ago

A 100 kg bungee jumper leaps from a bridge. The bungee cord has an un-streched equilibrium length of 10 m, and a spring constant

nika2105 [10]

Answer:

11.78meters

Explanation:

Given data

Mass m = 100kg

Length of cord= 10m

Spring constant k= 35N/m

At the greatest vertical distance, the spring potential energy is equal to the gravitational potential energy

That is

Us=Ug

Us= 1/2kx^2

Ug= mgh

1/2kx^2= mgh

0.5*35*10^2= 100*9.81*h

0.5*35*100=981h

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h= 1750/981

h= 1.78

Hence the bungee jumper will reach 1.78+10= 11.78meters below the surface of the bridge

6 0

3 years ago

Read 2 more answers

if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.​

if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.