The angular speed of the device is 1.03 rad/s.
<h3>What is the conservation of angular momentum?</h3>
A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.
Using the conservation of angular momentum

Here, = the system's angular momentum before the collision
= 0 + mv
= (0.005)(450)(0.752)
= 1.692 kgm²/s
The moment of inertia of the system is given by
I = 2(M₁R₁² + M₂R₂²)+ mR₁²
= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²
= 1.6292 kgm²
Here, = Iω
So,
1.692 = 1.6292(ω)
ω = 1.03 rad/s
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Answer:
the solid particles that settle down at the bottom of the container are known as sediment.
Explanation:
Answer: negative
Explanation: it may seem that neutrons would be negative but neutrons are neutral, protons are positive, and electrons are negative
Part a)
kinetic energy of the hammer will be

here we know that
m = 4 kg
v = 6 m/s
now by the equation of kinetic energy we have


Part b)
for finding the force we will have

here we know that



now from above equation we have


now by Newton's II law we have


so it requires 720 N.
Answer:
d = 20.25 m
Explanation:
h = 6m, V = 14 m/s, θ=14°
⇒ Vx=V × Cosθ=13.58 m/s and Vy = V × Sinθ=3.39 m/s
to find time t by h=-Vy t + 1/2 g t² (after putting value and simplifying) (-ve for downward motion)
4.9 t² - 3.39 t - 6 =0
⇒ t=1.5 sec (ignoring -ve root)
Now Vx = d/t
13.5 m/s = d / 1.5 s ⇒ d = 20.25 m