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3 years ago

Which statement is a characteristic of a concave lens

Physics

1 answer:

Free_Kalibri [48]3 years ago

5 0

<em>"A concave lens is thinner at the center than it is at the edges."</em>

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A +2e charge is at the point (-1,0) mm in the x,y plane. A –e charge is at the point (0,1) mm. What is the electric field at the

Gennadij [26K]

Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

Goodluck

Explanation:

4 0

2 years ago

8. What is the frequency of green light waves that have a wavelength of 5.2 x 10-7 m.? The speed of light is 3.0 x 108 m/s

o-na [289]

Answer:

$f=5.76\times 10^{14}\ Hz$

Explanation:

We need to find the frequency of green light having wavelength o $5.2\times 10^{-7}\ m$ . It can be calculated as follows :

$c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz$

So, the required frequency of green light is equal to $5.76\times 10^{14}\ Hz$ .

4 0

3 years ago

How do waves interact with our senses?

k0ka [10]

Answer:

well sound waves interact with our ears and light interacts with our vision

Explanation:

5 0

2 years ago

Read 2 more answers

Sound wave A delivers 2 J of energy in 2 s. Sound wave B delivers 10 J of energy in 5 s. Sound wave C delivers 2 mJ of energy in

Dmitry [639]

Answer:

In the order largest to smallest

Pc = Pb, Pa

Explanation:

Power = Energy expended/time

Pa = 2/2 = 1Watt

Pb = 10/5 = 2Watt

Pc = 2E-3/1E-3 = 2Watt

8 0

3 years ago

Radioactive plutonium−239 (t1/2 = 2.44 × 105 yr) is used in nuclear reactors and atomic bombs. If there are 3.50 × 102 g of the

madam [21]

Answer:

t = 4.41 10⁻⁴ years

Explanation:

For this exercise we must use the concept of average life time, which is the time in which the quantity and substance decays in half

$T_{1/2}$ = ln2 / λ

Let's calculate the decay constant of plutonium

λ = ln2 / $T_{1/2}$

λ = ln 2 / 2.44 10⁵

λ = 2.84 10⁻⁶ s⁻¹

Radioactive decay is a first order process

N = No e (-λ t)

Where N is the number of nuclei, the mass is this by molecular weight

m = N PM

m / PM = m₀ / PM e (- λ t)

m / m₀ = e (- λ t)

-λ t = ln (m / m₀)

t = -1 /λ ln (m/m₀)

t = - 1 / 2.84 10⁻⁶ ln (0.1 / 0.35)

t = 4.41 10⁻⁴ years

7 0

3 years ago