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vivado [14]
3 years ago
5

Which of the following yields a basic solution when dissolved in water? I. Nh3 ii. Na2o iii. Lioh iv. P4o10

Chemistry
1 answer:
emmainna [20.7K]3 years ago
8 0

<u>Answer:</u> The correct answer is Option 1, Option 2 and Option 3.

<u>Explanation:</u>

A base is defined as the substance which releases hydroxide ion when dissolved in water.

For the given options:

  • <u>Option 1:</u>  NH_3

When ammonia is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

NH_3+H_2O\rightarrow NH_4OH

  • <u>Option 2:</u>  Na_2O

When sodium oxide is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

Na_2O+H_2O\rightarrow 2NaOH

  • <u>Option 3:</u>  LiOH

When lithium hydroxide is dissolved in water, it produces aqueous lithium hydroxide which forms a basic solution.

LiOH+H_2O\rightarrow LiOH(aq.)

  • <u>Option 4:</u>  P_4O_{10}

When phosphorus pentoxide is dissolved in water, it produces phosphoric acid which forms an acidic solution.

P_4O_{10}+6H_2O\rightarrow 4H_3PO_4

Hence, the correct answer is Option 1, Option 2 and Option 3.

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Answer:

The answer is: +7

Explanation:

Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.

Perchlorate ion is a molecule with a chemical formula: ClO₄⁻

The oxidation state of oxygen in ClO₄⁻ = -2,

the total charge on the ClO₄⁻ molecule = -1,

let the oxidation state of chlorine be x

<u><em>As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.</em></u>

⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule

⇒ x + (-2) × 4 = -1

⇒ x + (-8) = -1

⇒ x = -1 + 8 = +7

⇒<u> </u><u>x = +7</u>

<u>Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7</u>

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200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?
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  • M be molar concentration
  • V be volume

So

  • M1=0.845M
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  • V2=0.6L
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\\ \tt\rightarrowtail M1V1=M2V2

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