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lesya [120]
3 years ago
5

Greg and Tabitha are jogging together. At time t = 0, they are both traveling at a speed of 4 m/s, but Greg is 8 m ahead of Tabi

tha. Tabitha accelerates at a rate of 1.5 m/s2 and Greg accelerates at a rate of 1.0 m/s2.
a. Write an expression for Greg's position. Plug in all the values you can to simplify the expression. (1 point)

b. Write an expression for Tabitha's position. Plug in all the values you can to simplify the expression. (1 point)

c. How long does it take Tabitha to catch up to Greg? (1 point)

d. How far has Tabitha run while catching up to Greg? (1 point)
Physics
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

The answer to question is below

Explanation:

Data

t1 = 0

vo = 4 m/s

a)

      d = vot + \frac{1}{2} at^{2}

      d = 4t + \frac{1}{2} (1)t^{2} + 8

      d = 8 + 4t + \frac{t^{2} }{2}

b)

      d = 4t + \frac{1}{2} (1.5)t^{2}

      d = 4t + 0.75t^{2}

c)    

       8 + 4t + \frac{t^{2} }{2}  =  4t + 0.75t^{2}

       4t + \frac{1}{2} t^{2} + 8 = 4t + \frac{1}{2} (1.5)t^{2} \\

       0.75t^{2} - 0.5t^{2}  = 8

       0.25t^{2} = 8

                      t² = 32

                      t = 5.66 s

d)

      d = 4(5.66) + 0.75(5.66)²

      d = 22.64 + 24.02

      d = 46.67 m

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[A] Write an expression for the equivalent resistance of three resistors connected in parallel.[ no derivation needed]
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1) R1 + ((R2 × R3)/(R2 + R3))

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1) We can see that resistors R2 and R3 are in parallel.

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