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MrRa [10]
4 years ago
15

A radioactive nuclide that is used for geological dating has an atomic number of 19 and mass number 40. Which is the symbol of t

his nuclide?

Chemistry
2 answers:
Alina [70]4 years ago
7 0
The mass number goes on top, and the atomic number goes on bottom. 
Therefore, the answer is C:
40
     K
19

aleksklad [387]4 years ago
3 0

Answer:

C. 40/19 K

Explanation:

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Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
Describe the capillary action in acetone compared to water
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Capillary action is defined as the ability of a liquid to go up a narrow space without the help or opposition of external forces. One of the most important factors affecting capillary action is the intermolecular forces within a substance. The higher the IMF, the greater the capillary action. The H-bonding in water gives it greater IMF than acetone, so water has greater capillary action.
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To make a 6.50M solution, how many moles of solute will be needed if 12.0 liters of solution are required
avanturin [10]

Answer:

78 moles of the solute

Explanation:

From the question;

  • Molarity of the solution is 6.50 M
  • Volume of the solution is 12.0 L

We want to determine the number of moles needed

We need to know that;

Molarity = Number of moles ÷ Volume

Therefore;

Number of moles = Molarity × Volume

Hence;

Number of moles = 6.50 M × 12.0 L

                             = 78 moles

Thus, the moles of the solute needed is 78 moles

8 0
3 years ago
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