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Norma-Jean [14]
3 years ago
14

In order to "see" something smaller than about 200 nm, an electron microscope can be used. an electron would have to be travelin

g at ___________ m/s in order to have a de broglie wavelength of 200 nm.
Physics
1 answer:
Damm [24]3 years ago
3 0
<span>3640 m/s The de Broglie wavelength of a particle is expressed by the equation: λ = h/p where λ = wavelength h = Planck constant p = momentum so let's solve for momentum and the substitute the known values and calculate: λ = h/p λp = h p = h/λ p = 6.62607004x10^-34 Js/2x10^-7 m p = 6.62607004x10^-34 kg*m^2/s^2 * s/2x10^-7 m p =3.31303502x10^-27 kg*m/s Now momentum is defined as mass times velocity. And the mass of an electron is 9.10938356×10^-31 kg. So p = mv p/m = v 3.31303502x10^-27 kg*m/s / 9.10938356×10^-31 kg = v 3.63694754774384x10^3 m/s = v Rounding to 3 significant figures gives 3.64x10^3 m/s or 3640 m/s. That velocity is low enough that we don't need to worry about relativistic effects.</span>
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A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius
ahrayia [7]

Answer:

The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.

at r < R:

Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.

E = 0.

at R < r < 2R:

The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.

at 2R < r:

The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.

Explanation:

Gauss’ Law is straightforward when applied to spheres. The area of the sphere is A = 4\pi r^2, and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.

3 0
3 years ago
The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c
Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ  = 0.23805 N-m

so

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

7 0
3 years ago
1. Write the following degrees in radian measure
svp [43]
C is the right answer

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6 0
3 years ago
Two billiard balls (each with mass equal to 170 g) collide head-on along the same line. Billiard ball A originally traveled east
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Answer:

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5 0
3 years ago
Which is the higher temperature? (Assume temperatures to be exact numbers.)(a)1.)265°C or 265°F?2.)265°C3.)265°F 4.)They are the
vazorg [7]

Remember the following formulas to convert temperatures between Farenheit and Celsius:

\begin{gathered} \text{ Farenheit to Celsius:} \\ C=\frac{5(F-32)}{9} \\  \\ \text{ Celsius to Farenheit:} \\ F=\frac{9}{5}C+32 \end{gathered}

Convert all the temperatures to Celsius to compare them.

<h2>Part a)</h2>

Convert 265ºF to Celsius:

\begin{gathered} C=\frac{5(F-32)}{9} \\  \\ =\frac{5(265-32)}{9} \\  \\ =129.444... \end{gathered}

Then, 265ºF is equal to 129.444...ºC. Then, 265ºC is higher than 265ºF.

The correct choice is option 2) 265ºC.

Part b)

Convert 370ºF to Celsius:

\begin{gathered} C=\frac{5(F-32)}{9} \\  \\ =\frac{5(370-32)}{9} \\  \\ =187.777...ºC \end{gathered}

Then, 370ºF is equal to 187.777...ºC. Then, 200ºC is higher than 370ºF.

The correct choice is option 2) 200ºC.

7 0
1 year ago
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