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Norma-Jean [14]
3 years ago
14

In order to "see" something smaller than about 200 nm, an electron microscope can be used. an electron would have to be travelin

g at ___________ m/s in order to have a de broglie wavelength of 200 nm.
Physics
1 answer:
Damm [24]3 years ago
3 0
<span>3640 m/s The de Broglie wavelength of a particle is expressed by the equation: λ = h/p where λ = wavelength h = Planck constant p = momentum so let's solve for momentum and the substitute the known values and calculate: λ = h/p λp = h p = h/λ p = 6.62607004x10^-34 Js/2x10^-7 m p = 6.62607004x10^-34 kg*m^2/s^2 * s/2x10^-7 m p =3.31303502x10^-27 kg*m/s Now momentum is defined as mass times velocity. And the mass of an electron is 9.10938356×10^-31 kg. So p = mv p/m = v 3.31303502x10^-27 kg*m/s / 9.10938356×10^-31 kg = v 3.63694754774384x10^3 m/s = v Rounding to 3 significant figures gives 3.64x10^3 m/s or 3640 m/s. That velocity is low enough that we don't need to worry about relativistic effects.</span>
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A plane lands on a runway with a speed of 115 m/s, moving east, and it slows to a stop in 13.0 s. What is the magnitude (in m/s2
marin [14]

Answer:

<em> The planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S.I Unit of acceleration is m/s². Acceleration is a vector quantity because it can be represented both in magnitude and in direction.

Acceleration can be represented mathematically as

a = v/t.................................... Equation 1

Where a = acceleration, v = velocity, t= time.

<em>Given: v = 115 m/s, t = 13.0 s</em>

<em>Substituting these values into equation 1</em>

<em>a = 115/13</em>

<em>a = 8.846 m/s² moving east</em>

<em>Thus the planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

4 0
2 years ago
Enter an expression, in terms of defined quantities and g, for the force that the scale under left pillar shows
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The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g

<h3>What is a Scale?</h3>

This can be defined as a balance or any of various other instruments or devices for weighing.

The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .

Read more about Force here brainly.com/question/4515354

5 0
1 year ago
A basketball player can leap upward 0.43 m. how long does he remain in the air? use an acceleration due to gravity of 9.80 m/s2
MArishka [77]
From the equations of linear motion,
v² = u² + 2as where v is the final velocity, u is the initial velocity and a is the gravitational acceleration, and s is the displacement,
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                = 2×9.81×0.43
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Hence the initial velocity is 2.905 m/s
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but, v = 0
Thus, u= gt
Hence, t = u/g
              = 2.905/9.81
              = 0.296 seconds


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3 years ago
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Answer:

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Explanation:

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