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Norma-Jean [14]
3 years ago
14

In order to "see" something smaller than about 200 nm, an electron microscope can be used. an electron would have to be travelin

g at ___________ m/s in order to have a de broglie wavelength of 200 nm.
Physics
1 answer:
Damm [24]3 years ago
3 0
<span>3640 m/s The de Broglie wavelength of a particle is expressed by the equation: λ = h/p where λ = wavelength h = Planck constant p = momentum so let's solve for momentum and the substitute the known values and calculate: λ = h/p λp = h p = h/λ p = 6.62607004x10^-34 Js/2x10^-7 m p = 6.62607004x10^-34 kg*m^2/s^2 * s/2x10^-7 m p =3.31303502x10^-27 kg*m/s Now momentum is defined as mass times velocity. And the mass of an electron is 9.10938356×10^-31 kg. So p = mv p/m = v 3.31303502x10^-27 kg*m/s / 9.10938356×10^-31 kg = v 3.63694754774384x10^3 m/s = v Rounding to 3 significant figures gives 3.64x10^3 m/s or 3640 m/s. That velocity is low enough that we don't need to worry about relativistic effects.</span>
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A ball is thrown horizontally. What is the ball's acceleration at its highest point
natka813 [3]
At the highest point of motion the ball comes to rest momentarily,but it is being pulled down due to the effect of gravity,so its net acceleration is downwards. So,just after that point,it starts falling downwards.
4 0
3 years ago
To find some of the parameters characterizing an object moving in a circular orbit.The motivation for Isaac Newton to discover h
tamaranim1 [39]

Answer:

K = \frac{GMm}{2r}

T^2 = 4\pi^2(\frac{r^3}{GM})

Explanation:

As we know that for a satellite the force of gravitation is equal to the centripetal force

so we will have

F = \frac{GMm}{r^2}

\frac{mv^2}{r} = \frac{GMm}{r^2}

so we know that kinetic energy is given as

K = \frac{1}{2}mv^2

so we have

K = \frac{GMm}{2r}

now for time period we know

T = \frac{2\pi r}{v}

from above expression of kinetic energy we have

v = \sqrt{\frac{GM}{r}}

so we have

T = \frac{2\pi r}{\sqrt{\frac{GM}{r}}}

so square of time period is given as

T^2 = 4\pi^2(\frac{r^3}{GM})

3 0
3 years ago
What is a star's main fuel during its lifetime? A. hydrogen B. carbon C. helium D. oxygen
Flura [38]
<span>The star's main fuel during its lifetime is hydrogen. It is said that a star is composed of 97% hydrogen and 3% helium. Once the hydrogen of a star is gone, the star becomes old because it burns hydrogen during its lifetime.</span>
6 0
3 years ago
A pendulum is 0.760 m long, and the bob has a mass of 1,00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. The tens
bixtya [17]

Answer:

  T = 13.17 N

the correct one is there is a digested centripetal acceleration towards upward

Explanation:

For this exercise we can use Newton's second law at the bottom of the pendulum's path

we will assume that the upward direction is positive

              T - W = m a

in this case it is describing a circle the acceleration is central

              a = v² / R

where the radius of the trajectories equals the length of the pendulum

             R = L

we substitute

            T = mg + m v² / L

             T = m (g + v² / L)

When reviewing the different statements, the correct one is there is a digested centripetal acceleration towards upward

let's calculate the tension of the rope

             T = 1 (9.8 + 1.6 2 / 0.760)

             T = 13.17 N

6 0
3 years ago
Which factors affect the electrical force between two objects?.
xenn [34]

Answer:

the distance between the particles and the amount of electric charge that they carried.

Explanation:

hope this helps

8 0
3 years ago
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