One Nitrogen and three iodine's react to form two nitrogen triiodides.
The balanced chemical reaction is:
<span>C6H12 + 9O2 = 6CO2 + 6H2O
We are given the amount of </span><span>C6H12 to be used for the reaction. THis will be the starting point for the calculations.
1.900 g </span>C6H12 ( 1 mol C6H12/ 84.18 g C6H12) ( 6 mol CO2 / 1 mol <span>C6H12) (44.01 g /mol ) = 5.96 g CO2
</span>1.900 g C6H12 ( 1 mol C6H12/ 84.18 g C6H12) ( 6 mol H2O / 1 mol <span>C6H12) (18.02 g /mol ) = 2.44 g H2O
</span>
Answer: 8.57 ml of KOH is required to reach the equivalence point.
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus 8.57 ml of KOH is required to reach the equivalence point.