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ZanzabumX [31]
3 years ago
9

Spell out the full name of the compound.

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0

Answer:

2–methylpropene.

Explanation:

To successfully name the compound given in the question, we must observe the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.

4. Combine the above to obtain the name of the compound.

Now, let us determine the name of the compound. This is illustrated below:

1. The functional group of the compound is the double bond i.e the compound is an alkene.

2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.

3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.

4. Therefore, the name of the compound is:

2–methylpropene

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Answer:

mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

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Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

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Answer:

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