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ZanzabumX [31]
3 years ago
9

Spell out the full name of the compound.

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0

Answer:

2–methylpropene.

Explanation:

To successfully name the compound given in the question, we must observe the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.

4. Combine the above to obtain the name of the compound.

Now, let us determine the name of the compound. This is illustrated below:

1. The functional group of the compound is the double bond i.e the compound is an alkene.

2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.

3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.

4. Therefore, the name of the compound is:

2–methylpropene

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3Cu + 8HNO = 3Cu(NO3)2 +2NO + 4H2O
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Taking into account the reaction stoichiometry, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 Cu+ 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Cu: 3 moles
  • HNO₃: 8 moles
  • Cu(NO₃)₂: 3 mole
  • NO: 2 moles
  • H₂O: 4 moles

The molar mass of the compounds is:

  • Cu: 63.55 g/mole
  • HNO₃: 63 g/mole
  • Cu(NO₃)₂: 187.55 g/mole
  • NO: 30 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Cu: 3 moles ×63.55 g/mole= 190.65 grams
  • HNO₃: 8 moles ×63 g/mole= 504 grams
  • Cu(NO₃)₂: 3 moles ×187.55 g/mole= 562.65 grams
  • NO: 2 moles ×30 g/mole= 60 grams
  • H₂O: 4 moles ×18 g/mole= 72 grams

<h3>Mass of Cu(NO₃)₂ produced</h3>

The following rule of three can be applied: if by reaction stoichiometry 504 grams of HNO₃ form 562.65 grams of Cu(NO₃)₂, 4.69 grams of HNO₃ form how much mass of Cu(NO₃)₂?

mass of Cu(NO_{3} )_{2} =\frac{4.69 grams of HNO_{3}  x562.65 grams of Cu(NO_{3} )_{2} }{504 grams of HNO_{3} }

<u><em>mass of Cu(NO₃)₂=  5.2634 grams</em></u>

Then, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

7 0
2 years ago
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