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3 years ago

Spell out the full name of the compound.

Chemistry

1 answer:

scoundrel [369]3 years ago

7 0

Answer:

2–methylpropene.

Explanation:

To successfully name the compound given in the question, we must observe the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.

4. Combine the above to obtain the name of the compound.

Now, let us determine the name of the compound. This is illustrated below:

1. The functional group of the compound is the double bond i.e the compound is an alkene.

2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.

3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.

4. Therefore, the name of the compound is:

2–methylpropene

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In a heat engine, if 500 J of heat enters the system, and the piston does 300 J of work, what is the final internal (thermal) en

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Answer: The final energy is 1,700 J

Explanation: According to first law of thermodynamics:

$\Delta U=q+w$

$\Delta U=U_2-U_1$ =Final energy-initial energy=Change in internal energy

q = heat absorbed or released

w = work done by or on the system

w = work done by the system= $-P\Delta V$ {Work done by the system is negative as the final volume is greater than initial volume}

q = +500J {Heat absorbed by the system is positive}

w = work done by the system = -300J

$U_2-1500J=+500J-300J$

$U_2=1700J$

6 0

3 years ago

Read 2 more answers

The isotope 90_Sr has a half-life of 28.8 years. What is the activity, measured in atoms/second of a 50 mg sample of "Sr? (10 pt

blsea [12.9K]

Answer:

$2.5523\times 10^{11} atoms/seconds$ is the activity, measured in of a 50 mg sample of 90-Sr.

Explanation:

Half life of the 90-Sr , $t_{1/2}= 28.8 years$

Activity coefficient of the 90-Sr = $\lambda$

$\lambda =\frac{0.693}{28.8 years}=0.0240625 year^{-1}$

Mass of 90-Sr = 50 mg = 0.050 g

Molecular mass of 90-Sr = 90 g/mol

Moles of 90-Sr = $\frac{0.050 g}{90 g/mol}=0.0005555 mol$

Number of atom in 0.0005555 moles of 90-Sr:

$0.0005555 mol\times 6.022\times 10^{23} mol^{-1}=3.3455\times 10^{20} atoms$

$\lambda =0.0240625 year^{-1}=\frac{0.0240625}{3.154\times 10^7 s}=7.6292\times 10^{-10} s^{-1}$

1 year = $3.154\times 10^7 seconds$

Activity measured in atoms per seconds:

= Number of atoms × $\lambda$

$=3.3455\times 10^{20} atoms\times 7.6292\times 10^{-10} s^{-1}$

$=2.5523\times 10^{11} atoms/s$

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3 years ago

What is the pH of a 1.30 M solution of KF?

Troyanec [42]

I don’t know I’m just answering for points I don’t know 12

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3 years ago

Given 4.80g of ammonium carbonate, find:

V125BC [204]

Answer:

1) 0.05 mol.

2) 0.1 mol.

3) 0.05 mol.

4) 0.4 mol.

5) 2.4 x 10²³ molecules.

Explanation:

1) Number of moles of the compound:

no. of moles of ammonium carbonate = mass/molar mass = (4.80 g)/(96.09 g/mol) = 0.05 mol.

2) Number of moles of ammonium ions :

Ammonium carbonate is dissociated according to the balanced equation:

(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of NH₄⁺ ions in 0.05 mol of (NH₄)₂CO₃ = (2.0)(0.05 mol) = 0.1 mol.

3) Number of moles of carbonate ions :

Ammonium carbonate is dissociated according to the balanced equation:

(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of CO₃²⁻ ions in 0.05 mol of (NH₄)₂CO₃ = (1.0)(0.05 mol) = 0.05 mol.

4) Number of moles of hydrogen atoms:

Every 1.0 mol of (NH₄)₂CO₃ contains:

2.0 moles of N atoms, 8.0 moles of H atoms, 1.0 mole of C atoms, and 3.0 moles of O atoms.

∴ The no. of moles of H atoms in 0.05 mol of (NH₄)₂CO₃ = (8.0)(0.05 mol) = 0.4 mol.

5) Number of hydrogen atoms:

It is known that every mole of a molecule or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

Using cross multiplication:

1.0 mole of H atoms contains → 6.022 x 10²³ atoms.

0.4 mole of H atoms contains → ??? atoms.

∴ The no. of atoms in 0.4 mol of H atoms = (6.022 x 10²³ molecules)(0.4 mole)/(1.0 mole) = 2.4 x 10²³ molecules.

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4 years ago

Which pattern(s) may be observed from the arrangement of elements in the periodic table? Select all that apply.

Neporo4naja [7]

It’s organized by the atomic number which is the protons so the answer is A although they can be organized through groups and periods if valance electrons are included

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3 years ago