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Dafna11 [192]
3 years ago
10

Ill give brainliest! 1. Which item below describes a quick change to

Physics
2 answers:
Damm [24]3 years ago
8 0

Answer:

I believe it's <u>D. a glacier flattening the land below it​.</u>

stiks02 [169]3 years ago
7 0
The best answer to go with is b
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Identify which one is chemical change, chemical property,physical change and physical property
Ulleksa [173]

Answer:

Heat conductivity: Physical property

Silver tarnishing: chemical change

Sublimation: physical change

Magnetizing steel: physical property

Length of a metal object: physical property

Shortening melting: physical property

exploding dynamite: chemical change

combustible: chemical property

water freezing: physical change

Acid resistance: chemical property

brittleness: physical property

milk souring: chemical change

baking bread: chemical change

Explanation:

First you need to understand the differences between physical and chemical change; physical and chemical property.

<u>Physical properties vs chemical properties:</u>

Physical properties are properties that you can observe without changing the substance's composition. This means you can measure these properties without changing them chemically.

Chemical properties, on the other hand, are properties are not as direct. These properties are generally determined by the way the react with other substances changing their composition.

<u>Physical changes vs chemical changes:</u>

A substance that undergoes physical change does not change in chemical composition. They may look physically different in terms of size and shape, but overall, their chemical composition remains constant. The best example would be water. Water can change phases, from solid to liquid when they melt. Essentially, they look like different substances, but the change is only physical and not chemical.

Chemical change, is different by the fact that they change in chemical composition. Bonds are broken and/or made through the reaction, which changes them not only physically but chemically as well. Some of the most indicative signs of a chemical change occurring are: change in color, odor, production of gas, production of light/heat.

4 0
3 years ago
Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section
ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER  E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W /  ( E × π × P )     ...................1

put here all value

σ = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

1300 × 10^{-24} = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

solve it and we get W

W = 249.56 × 10^{-2}

so elastic partial width is 2.49 eV

8 0
4 years ago
2. A Plate 0.02 mm distance from a fixed Plate moves at a velocity Of 0.6mls and requires a force of 1.962 N Per unit area to ma
Marizza181 [45]

Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So,  μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

5 0
3 years ago
Your little sister (mass 25 kg) is sitting in her little red wagon (mass 8.5 kg) at rest. You begin pulling her forward, acceler
Nata [24]

Answer:

Your little sister (mass 25.0  ) is sitting in her little red wagon (mass 8.50  at rest. You begin pulling her forward and continue accelerating her with a constant force for 2.35  at the end of which time she's moving at a speed of 1.80  .

(a) Calculate the impulse you imparted to the wagon and its passenger. (b) With what force did you pull on the wagon?

4 0
3 years ago
A rectangular block measures 4.1cm by 2.8cm by 2.1cm. calculate its volume given you answer to an appropriate number of signific
sattari [20]

Answer:

Volume =  24 cm^3

Explanation:

We recall that the volume of the box is calculated via the formula:

Volume = length * height * width

and that in a product, the number of significant figures for the result should coincide with the number of significant figures of the factor that has the least of them.

In this case, all measures have the same number of significant figures: two. so we calculate the product, and then limit the answer value to exactly two significant figures:

Volume = 4.1 cm * 2.8 cm * 2.1 cm = 24.108 cm^3, which must be rounded to two significant figures as: 24 cm^3

6 0
3 years ago
Read 2 more answers
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